Question

我有2个名单：

1）

FG       FG lot
12043267 6105552268 
12043267 6109552268  
12043267 6110552268  
12043267 6111552268

2）

item     item lot
43626551 610457472H 
43626551 610557472H 
43626551 610957471H 
43626551 610957472H 
43626551 611057472H 
43626551 611157471H 
43626551 611157472H

应该发生什么：

FG       FG lot      item lot    item
12043267 6105552268  610557472H  43626551 
12043267 6109552268  610957471H  43626551 
12043267 6110552268  611057472H  43626551 
12043267 6111552268  611157471H  43626551

总体思路：检查所有FG批次是否都有相应的项目批次。

棘手的部分是我需要查看前4位数字进行比较，然后才考虑是否有一个相应的项目批次。也就是说，我不在乎右边是否有3个，4个，5个，99个项目批次，只要至少有1个相应的项目批次。

我的代码：

DECLARE @FG NVARCHAR(30) = '12043267'
DECLARE @proddate datetime = '6/8/2016'
SET DATEFIRST 1;

SELECT DISTINCT

    t.item,
    t.lot,
    candylots.lot,
    candylots.item

FROM

    ISW_LPTrans AS t
    LEFT OUTER JOIN

        (SELECT TOP 1

        --t.lp_num,
        t.item,
        t.lot

        FROM

            ISW_LPTrans AS t
            INNER JOIN item AS i on i.item = t.item

        WHERE

            i.product_code = 'RM-Candy' AND
            t.trans_date = '6/8/2016' AND
            t.trans_type = 'I' AND
            t.ref_num IN

                (

                    SELECT

                        j.job

                    FROM

                        job AS j

                    WHERE

                        j.item = '12043267' AND
                        j.job_date = '6/6/2016'

                )

            AND t.ref_line_suf IN

                (

                    SELECT

                        j.suffix

                    FROM

                        job AS j

                    WHERE

                        j.item = '12043267' AND
                        j.job_date = '6/6/2016'     

                ) 

        GROUP BY

            t.item,
            t.lot

        ) AS candylots ON LEFT(candylots.lot, 4) = LEFT(t.lot, 4)

WHERE

    t.ref_num = 'N000016174' AND
    t.ref_line_suf = 24 AND
    t.trans_type = 'F' AND
    t.item = '12043267' AND
    t.trans_date = '6/8/2016'

/*GROUP BY

    t.item,
    t.lot,
    candylots.lot,
    candylots.item*/

代码的作用：

FG       FG lot      item lot  item
12043267 6105552268  null      null 
12043267 6109552268  null      null 
12043267 6110552268  null      null 
12043267 6111552268  null      null

显然有些不对劲。有没有人知道实现这个目标的方法？

更新

我只尝试SELECTING两个列表的前四位数字并且它可以正常工作，但理想情况下我希望能够完整地写出这两个列表。< / p>

DECLARE @FG NVARCHAR(30) = '12043267'
DECLARE @proddate datetime = '6/8/2016'
SET DATEFIRST 1;

SELECT DISTINCT

    t.item,
    LEFT(t.lot,4) AS FG_lots,
    candylot.candy_lots,
    candylot.item

FROM

    ISW_LPTrans AS t
    LEFT OUTER JOIN

        (SELECT

            --t.lp_num,
            t.item,
            LEFT(t.lot,4) AS candy_lots

            FROM

                ISW_LPTrans AS t
                INNER JOIN item AS i on i.item = t.item

            WHERE

                i.product_code = 'RM-Candy' AND
                t.trans_date = '6/8/2016' AND --(SELECT DATEADD(DAY, 1-DATEPART(WEEKDAY, @proddate), @proddate)) AND
                t.trans_type = 'I' AND
                t.ref_num IN

                    (

                        SELECT

                            j.job

                        FROM

                            job AS j

                        WHERE

                            j.item = '12043267' AND
                            j.job_date = '6/6/2016'

                    )

                AND t.ref_line_suf IN

                    (

                        SELECT

                            j.suffix

                        FROM

                            job AS j

                        WHERE

                            j.item = '12043267' AND
                            j.job_date = '6/6/2016'     

                    ) 

            GROUP BY

                t.item,
                t.lot

            ) AS candylot ON candylot.candy_lots = LEFT(t.lot, 4)

WHERE

    t.ref_num = 'N000016174' AND
    t.ref_line_suf = 24 AND
    t.trans_type = 'F' AND
    t.item = '12043267' AND
    t.trans_date = '6/8/2016'

正确但不理想的结果：

item     FG_lots  candy_lots  item1
12043267 6105     6105        43626551 
12043267 6109     6109        43626551 
12043267 6110     6110        43626551 
12043267 6111     6111        43626551

Answer 1

它需要是这样的吗？

SELECT t.item, t.lot, i.FG, i.[FG lot]
FROM ISW_LPTrans as t
LEFT JOIN item as i
ON LEFT(i.[FG lot],4) = LEFT(t.lot,4);

还是太简单了？

SQL：LEFT OUTER JOIN重复某些行

1 个答案: