Question

我有这个xml，我想将它插入临时表中，包括单行中<salesorpurchase>节点内的值。这可能吗？

或者，您能告诉我如何删除<SalesOrPurchase>而不删除其内部文本吗？

<ItemServiceRet> 
    <ListID>80000012-1302270176</ListID> 
    <EditSequence>1302270195</EditSequence>
    <Name>2nd Floor Shop</Name>
    <FullName>2nd Floor Shop</FullName> 
    <IsActive>true</IsActive>
    <SalesOrPurchase>
        <Price>0.00</Price>
        <AccountRef> 
            <ListID>800000B3-1302260225</ListID>
            <FullName>Rent Income:Rent income 2ND FL:2nd Floor Shops</FullName> 
        </AccountRef>
    </SalesOrPurchase>
</ItemServiceRet> 
<ItemServiceRet> 
    <ListID>80000002-1277187768</ListID> 
    <EditSequence>1463398389</EditSequence>
    <Name>VAT 16%</Name> 
    <FullName>VAT 16%</FullName>
    <IsActive>true</IsActive> 
    <SalesOrPurchase>
        <PricePercent>16.00</PricePercent> 
        <AccountRef>
            <ListID>6B0000-1224749077</ListID> 
            <FullName>Vat account</FullName> 
        </AccountRef> 
    </SalesOrPurchase> 
</ItemServiceRet>

Answer 1

1）尝试以下查询将每个ItemServiceRet元素的数据插入一行（在这种情况下，因为有两个ItemServiceRet元素将插入两行：

DECLARE @XmlData XML = N'
<ItemServiceRet> 
    <ListID>80000012-1302270176</ListID> 
    <EditSequence>1302270195</EditSequence>
    <Name>2nd Floor Shop</Name>
    <FullName>2nd Floor Shop</FullName> 
    <IsActive>true</IsActive>
    <SalesOrPurchase>
        <Price>0.00</Price>
...
</ItemServiceRet>'

SELECT  ListID          = y.XmlCol.value('(ListID)[1]', 'VARCHAR(19)'),
        EditSequence    = y.XmlCol.value('(EditSequence)[1]', 'INT'),
        -- ...
        Price           = y.XmlCol.value('(SalesOrPurchase/Price)[1]', 'NUMERIC(9,2)'),
        PricePercent    = y.XmlCol.value('(SalesOrPurchase/PricePercent)[1]', 'NUMERIC(9,2)'),
        ListID2         = y.XmlCol.value('(SalesOrPurchase/AccountRef/ListID)[1]', 'VARCHAR(19)')
INTO    #Items
FROM    (VALUES (@XmlData)) x(XmlCol)/*or @XmlData.nodes*/
CROSS APPLY x.XmlCol.nodes(N'ItemServiceRet') y(XmlCol)

/*
Results:
(2 row(s) affected)
*/

此解决方案使用两种XML方法：nodes（将XML分为多行）和值（它从当前节点/元素中提取一个值）。

2）第二个解决方案是＆＃34;删除＆＃34; SalesOrderHeader节点因此：

SELECT  x.XmlCol.query('
    for $i in (ItemServiceRet)
        return
            <ItemServiceRet>
                <ListID>{$i/ListID/text()}</ListID> 
                <IsActive>{$i/IsActive/text()}</IsActive>
                <Price>{$i/SalesOrPurchase/Price/text()}</Price>
                <PricePercent>{$i/SalesOrPurchase/PricePercent/text()}</PricePercent>
                <AccountRef>
                    <ListID>{$i/SalesOrPurchase/AccountRef/ListID/text()}</ListID>  
                    <FullName>{$i/SalesOrPurchase/AccountRef/FullName/text()}</FullName> 
                </AccountRef>
            </ItemServiceRet>
') AS NewXmlCol
FROM    (SELECT (@XmlData)) x(XmlCol)

删除SQL Server 2008中的XML子节点元素

1 个答案: