您知道是否可以自行使用组件?如果是的话,在哪里阅读它?
我有下一个情况: 拥有mainItems列表,每个Main Item都有subItem(看起来像mainItem),每个subItem都可以拥有它自己的subItem等。 所以最好使用嵌套,但是如何?
答案 0 :(得分:35)
<强>更新强>
forwardRef()
不再需要了,因为directives
已移至NgModule.declarations
,因此递归组件不再需要在directives
上注册。
<强>原始强>
支持。您只需将组件添加到directives: []
装饰器中的@Component()
即可。因为装饰器出现在类之前,并且在声明它们之前无法引用类forwardRef()
。
import {Component, forwardRef, Input} from '@angular/core'
@Component({
selector: 'tree-node',
template: `
<div>{{node.name}}</div>
<ul>
<li *ngFor="let node of node.children">
<tree-node [node]="node"></tree-node>
</li>
</ul>
`
})
export class TreeNode {
@Input() node;
}
@Component({
selector: 'my-app',
template: `
<div>
<h2>Hello {{name}}</h2>
<tree-node [node]="node"></tree-node>
</div>
`,
directives: [TreeNode]
})
export class App {
constructor() {
this.name = 'Angular2 (Release Candidate!)'
}
node = {name: 'root', children: [
{name: 'a', children: []},
{name: 'b', children: []},
{name: 'c', children: [
{name: 'd', children: []},
{name: 'e', children: []},
{name: 'f', children: []},
]},
]};
}
Angular 2.0.0-beta.x Plunker example
另见Inject parent component of the same type as child component
答案 1 :(得分:5)
Angular 4 递归组件示例:https://plnkr.co/edit/IrW82ye4NKK8cYEPxsFc?p=preview
摘录链接示例:
//our root app component
import {Component, NgModule, VERSION, Input} from '@angular/core'
import {BrowserModule} from '@angular/platform-browser'
@Component({
selector: 'tree-node',
template: `
<div>{{node.name}}</div>
<ul>
<li *ngFor="let node of node.children">
<tree-node [node]="node"></tree-node>
</li>
</ul>
`
})
export class TreeNode {
@Input() node;
}
@Component({
selector: 'my-app',
providers: [],
template: `
<div>
<h2>Hello {{name}}</h2>
<tree-node [node]="node"></tree-node>
</div>
`
})
export class App {
constructor() {
this.name = 'Angular2 (Release Candidate!)'
}
node = {name: 'root', children: [
{name: 'a', children: []},
{name: 'b', children: []},
{name: 'c', children: [
{name: 'd', children: []},
{name: 'e', children: []},
{name: 'f', children: []},
]},
]};
}
@NgModule({
imports: [ BrowserModule ],
declarations: [ App, TreeNode ],
bootstrap: [ App ]
})
export class AppModule {}
此答案是社区维基,因为示例链接是从GünterZöchbauer的答案中复制的。我在问题正文中包含了代码以避免链接腐烂。
答案 2 :(得分:0)
使用ng-template
是解决递归DOM问题的最佳解决方案。
@Component({
selector: 'tree-node',
template: `
<ng-container *ngTemplateOutlet="tree;context:{node:node}">
</ng-container>
<ng-template #tree let-node="node">
<div>{{node.name}}</div>
<ul *ngIf="node.children && node.children.length > 0">
<ng-container *ngFor="let child of node.children">
<li>
<ng-container *ngTemplateOutlet="tree;context:{node:child}">
</ng-container>
</li>
</ng-container>
</ul>
</ng-template>
`
})
export class TreeNode {
@Input() node;
}
无需将组件添加到其directives: []
中的@Component()
中。
@Component({
selector: 'my-app',
template: `
<div>
<h2>Hello {{name}}</h2>
<tree-node [node]="node"></tree-node>
</div>
`
})
export class App {
node = {
name: 'root', children: [
{ name: 'a', children: [] },
{
name: 'b', children: [
{ name: 'b-1', children: [] },
{
name: 'b-2', children: [
{ name: 'b-2-1', children: [] },
{ name: 'b-2-2', children: [] },
{ name: 'b-2-3', children: [] }
]
}
]
},
{
name: 'c', children: [
{ name: 'c-1', children: [] },
{ name: 'c-2', children: [] }
]
},
]
};
}
输出:
HTML:
<tree-node>
<div>root</div>
<ul>
<li>
<div>a</div>
</li>
<li>
<div>b</div>
<ul>
<li>
<div>b-1</div>
</li>
<li>
<div>b-2</div>
<ul>
<li>
<div>b-2-1</div>
</li>
<li>
<div>b-2-2</div>
</li>
<li>
<div>b-2-3</div>
</li>
</ul>
</li>
</ul>
</li>
<li>
<div>c</div>
<ul>
<li>
<div>c-1</div>
</li>
<li>
<div>c-2</div>
</li>
</ul>
</li>
</ul>
</tree-node>