HTTP状态404 - / eclipse上的ServletHello / HelloServlet

时间:2016-06-09 02:57:47

标签: eclipse jsp servlets

我遇到了一个问题:当我调用index.jsp时,它不会调用servlet。

(1)index.jsp:

<%@ page language="java" contentType="text/html; charset=UTF-8"
    pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Insert title here</title>
</head>
<body>
<jsp:forward page="HelloServlet"/>
</body>
</html>

(2)servlet / HelloServlet.java:

package servlet;

import java.io.IOException;

import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

@WebServlet("/HelloServlet")
public class HelloServlet extends HttpServlet {

    private static final long serialVersionUID = 1L;


    public HelloServlet() {
        super();
        // TODO Auto-generated constructor stub
    }


    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        // TODO Auto-generated method stub
        request.getRequestDispatcher("welcome.jsp").forward(request, response);
    }
}

(3)welcome.jsp:

<body>
    Hello world
</body>

(4)web.xml

<?xml version="1.0" encoding="ISO-8859-1"?> 
<web-app xmlns="http://java.sun.com/xml/ns/j2ee" 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" 
version="2.4"> 

 <welcome-file-list>       
        <welcome-file>index.jsp</welcome-file>           
 </welcome-file-list>

 <servlet> 
     <servlet-name>hello</servlet-name> 
     <servlet-class>servlet.HelloServlet</servlet-class> 
 </servlet> 

 <servlet-mapping> 
     <servlet-name> hello </servlet-name> 
     <url-pattern> /welcome</url-pattern> 
 </servlet-mapping> 

</web-app> 

感谢您的光临和帮助

2 个答案:

答案 0 :(得分:0)

使用servlet的网址格式代替Scene代码中的类名:

jsp:forward

答案 1 :(得分:0)

编码没有问题。 检查您的项目名称。路径必须是http:localhost:8080 / Servlet / HelloServlet

这里的Servlet是项目名称。检查一次。

URL必须是/ HelloServlet。不是/ servlet / HelloServlet