Question

对于上下文，我正在开发一个项目，我希望从oracle数据库中自动生成oracle数据库中的主要ID。我正在使用Java Server Faces和Hibernate将项目添加到数据库中。

所以这是相关的代码部分：

创建序列语句

    CREATE SEQUENCE  "BIM***********"."SEQUENCE1"  MINVALUE 1 MAXVALUE     
    9999999999999999999999999999 INCREMENT BY 1 START WITH 1 CACHE 20  
    NOORDER NOCYCLE ;

创建表语句

  CREATE TABLE "BIMB2013WMMEE"."CLIENT" 
   (    "CLIENT_ID" VARCHAR2(20 BYTE) NOT NULL ENABLE, 
    "CLIENT_CODE" VARCHAR2(20 BYTE) NOT NULL ENABLE, 
    "CLIENT_NAME" VARCHAR2(20 BYTE) NOT NULL ENABLE, 
     CONSTRAINT "CLIENT_PK" PRIMARY KEY ("CLIENT_ID")
     USING INDEX PCTFREE 10 INITRANS 2 MAXTRANS 255 
     STORAGE(INITIAL 65536 NEXT 1048576 MINEXTENTS 1 MAXEXTENTS 2147483645
     PCTINCREASE 0 FREELISTS 1 FREELIST GROUPS 1
     BUFFER_POOL DEFAULT FLASH_CACHE DEFAULT CELL_FLASH_CACHE DEFAULT)
     TABLESPACE "USERS"  ENABLE
     ) SEGMENT CREATION IMMEDIATE 
     PCTFREE 10 PCTUSED 40 INITRANS 1 MAXTRANS 255 
     NOCOMPRESS LOGGING
     STORAGE(INITIAL 65536 NEXT 1048576 MINEXTENTS 1 MAXEXTENTS 2147483645
     PCTINCREASE 0 FREELISTS 1 FREELIST GROUPS 1
     BUFFER_POOL DEFAULT FLASH_CACHE DEFAULT CELL_FLASH_CACHE DEFAULT)
     TABLESPACE "USERS" ;

     CREATE OR REPLACE TRIGGER "BIMB2013WMMEE"."BEFORE" 
     before insert on "BIMB2013WMMEE"."CLIENT" 
     for each row 
        begin  
          if inserting then 
           if :NEW."CLIENT_ID" is null then 
              select SEQUENCE1.nextval into :NEW."CLIENT_ID" from dual; 
           end if; 
          end if; 
         end;

        /
         ALTER TRIGGER "BIMB2013WMMEE"."BEFORE" ENABLE;

这是违规的Java代码（据我所知）

@Entity
@Table (name="client")
public class Client {

    //Fields
    @Id
    @GeneratedValue(strategy=GenerationType.SEQUENCE)
    @Column(name="CLIENT_ID")
    private String id;

以下是来自Eclipse的错误消息：

Hibernate: select hibernate_sequence.nextval from dual
Jun 06, 2016 9:19:06 AM org.hibernate.engine.jdbc.spi.SqlExceptionHelper     
logExceptions
WARN: SQL Error: 2289, SQLState: 42000
Jun 06, 2016 9:19:06 AM org.hibernate.engine.jdbc.spi.SqlExceptionHelper    
logExceptions
ERROR: ORA-02289: sequence does not exist

Jun 06, 2016 9:19:06 AM    
org.hibernate.engine.jdbc.connections.internal.DriverManagerConnectionProviderImpl stop
INFO: HHH10001008: Cleaning up connection pool     [jdbc:oracle:thin:@endeavour.us.manh.com:1523/pso11r2f]
Exception in thread "main" org.hibernate.exception.SQLGrammarException: could not extract ResultSet
Caused by: java.sql.SQLSyntaxErrorException: ORA-02289: sequence does not exist

Answer 1

在实体上使用@SequenceGenerator注释，并使用序列生成器名称在generator注释中指定@GeneratedValue属性，如下所示：

@Entity
@Table (name="client")
@SequenceGenerator(name="sequence1",sequenceName="BIM***********.SEQUENCE1",
allocationSize=1, initialValue=1)
public class Client {

    //Fields
    @Id
    @GeneratedValue(strategy=GenerationType.SEQUENCE, generator="sequence1")
    @Column(name="CLIENT_ID")
    private String id;

Answer 2

尝试使用@SequenceGenerator + @GeneratedValue注释。

@Id
@SequenceGenerator(name="sequence1",sequenceName="BIM***********.SEQUENCE1")
@GeneratedValue(generator="sequence1")
@Column(name="CLIENT_ID")
private String id;

使用序列自动设置Oracle主键

2 个答案: