我想突出显示一行,其中包含数据来自后端的行的详细信息。我有一个名称地址和链接的表。一旦我点击该链接的链接详细信息显示。每个链接都不包含数据。所以我想只突出显示包含数据的行。这是我的代码: service.js:
(function(){
angular.module('myApp').service('detailService',detailService);
function detailService($http,$q){
var user={},
baseUrl="http://localhost:3000/form/detail";
var deferred =$q.defer();
this.getAllUSer = function(){
console.log('in getAllUser');
return $http.get(baseUrl).then(function(response){
user=response.data;
deferred.resolve(user);
return deferred.promise
},function(error){
deferred.reject(error);
return deferred.promise
});
},
this.getNameDetail=function(comp_id){
console.log('inside Record');
return $http.get(baseUrl + '/record/' + comp_id)
.success(function(response){
deferred.resolve(response.data);
return deferred.promise;
},function(error){
deferred.reject(error);
return deferred.promise;
});
},
this.getRecordDetail=function(comp_id){
console.log('inside Record');
return $http.get(baseUrl + '/' + comp_id)
.success(function(response){
deferred.resolve(response.data);
return deferred.promise;
},function(error){
deferred.reject(error);
return deferred.promise;
});
}
}
})();
controller.js:
(function(){
angular.module('myApp').controller('detailCtrl',detailCtrl);
function detailCtrl($scope,detailService,$stateParams,$state){
var userId=$stateParams.userId;
$scope.user=null;
$scope.cur_record=null;
$scope.name=null;
$scope.getUser =function(){
console.log('inside controller');
detailService.getAllUSer().then(function(response){
$scope.user=response;
console.log($scope.user);
});
},
$scope.getName =function(comp_id){
console.log('inside record controller');
detailService.getNameDetail(comp_id).then(function(data){
$scope.name=data.data;
console.log($scope.name);
$state.go('detail', {'userId':comp_id});
});
},
$scope.getRecord =function(comp_id){
console.log('inside record controller');
detailService.getRecordDetail(comp_id).then(function(data){
$scope.cur_record=data.data;
console.log($scope.cur_record);
$state.go('detail', {'userId':comp_id});
});
},
$scope.getRecordName=function(){
$scope.getRecord(userId);
},
$scope.get=function(){
$scope.getName(userId);
}
}
})();
模板:
<div class="row-fluid">
<div class="col-md-10">
<table class="table table-bordered main" ng-init="getUser()">
<thead>
<tr>
<th>sr_no</th>
<th>comp_id</th>
<th>name</th>
<th>view</th>
</tr>
</thead>
<tbody >
<tr ng-repeat="x in user">
<td>{{$index+1}}</td>
<td>{{x.comp_id}}</td>
<td>{{x.name}}</td>
<td ng-click="getRecord(x.comp_id)"><a href="">view</a></td>
</tr>
</tbody>
</table>
</div>
<div ui-view></div>
</div>
答案 0 :(得分:0)
如果x.comp_id具有值
,则可以按ng-style高亮显示行 <tr ng-repeat="x in user" ng-style="x.comp_id&&{'color':'red'}">
<td>{{$index+1}}</td>
<td>{{x.comp_id}}</td>
<td>{{x.name}}</td>
<td ng-click="getRecord(x.comp_id)"><a href="">view</a></td>
</tr>
参见示例fiddle