我正在制作一个密码强度检查器作为学校项目，但我很难找到一种方法来检查密码中有多少整数，因此我在三个方面检查密码，但我无法弄清楚如何检查整数。如果你们可以帮助我的解决方案可以包括更好的re库。谢谢！
到目前为止，这是我的问题代码。
import re
i_pwdStrength = i_pwdLength + i_pwdChar + i_pwdInt
i_pwdLength = 0
i_pwdChar = 0
i_pwdInt = 0
i_attempts = 0
numbAttemps = int(input("Enter the amount of passwords you would like to check \n(MUST BE A NUMBER)"))
pwd = input("Enter Password")
while numbAttempts < i_attempts
pwd = pwd.lower()
i_pwdLength = pwd.length
if i_pwdLength <= 3:
i_pwdLength = 1
elif i_pwdLength > 3 && <= 6:
i_pwdLength = 2
elif i_pwdLength > 6 && <= 9:
i_pwdLength = 3
else i_pwdLength > 9:
i_pwdLength = 4
i_pwdChar = #This is a very long way of writing this code as I could not find a way to compress these lines. I may have used the 'or' command but I could not
if re.search(r'[x]',pwd): # work out how to integrate it and i thought that this code looked neater
i_pwdChar = 1
elif re.search(r'[w]'pwd):
i_pwdChar = 1
elif re.search(r'[y]'pwd):
i_pwdChar = 1
elif re.search(r'[z]'pwd):
i_pwdChar = 1
elif re.search(r'[x]',pwd) and re.search(r'[w]',pwd):
i_pwdChar = 2
elif re.search(r'[x]',pwd) and re.search(r'[y]',pwd):
i_pwdChar = 2
elif re.search(r'[x]',pwd) and re.search(r'[z]',pwd):
i_pwdChar = 2
elif re.search(r'[w]',pwd) and re.search(r'[y]',pwd):
i_pwdChar = 2
elif re.search(r'[w]',pwd) and re.search(r'[z]',pwd):
i_pwdChar = 2
elif re.search(r'[y]',pwd) and re.search(r'[z]',pwd):
i_pwdChar = 2
elif re.search(r'[w]',pwd) and re.search(r'[x]',pwd) and re.search(r'[y]',pwd):
i_pwdChar = 3
elif re.search(r'[z]',pwd) and re.search(r'[x]',pwd) and re.search(r'[y]',pwd):
i_pwdChar = 3
elif re.search(r'[w]',pwd) and re.search(r'[z]',pwd) and re.search(r'[y]',pwd):
i_pwdChar = 3
else re.search(r'[w]',pwd) and re.search(r'[x]',pwd) and re.search(r'[y]',pwd) and re.search(r'[z]',pwd)
i_pwdChar = 4
由于我收到的所有帮助，我已经完成了代码。
import re
i_numbAttempts = int(input("How many passwords do you want to try?\nMUST BE A NUMBER!")) # Determines how many times the while loop further down
attempts = 0 # sets the variable attempts to 0 to ensure that the while loop works # repeats itself
while i_numbAttempts > attempts: # while the passwords entered is more than attempts:
pwd = input("Enter Password: ") # user enters password to check
pwd = pwd.lower() # sets the password to lowercase (QjwtwWyeRvgTRDU would become qjwtwwyervgtrdu)
if len(pwd) == 0: # if the user does not enter a password, it outputs: You must ypre something!
print("You must type something!")
i_pwdLength = 0
elif len(pwd) >= 1 and len(pwd) <= 3: # if the length is a certain length,
i_pwdLength = 1 # it will assign a corresponding value to the i_pwdLength variable
elif len(pwd) > 3 and len(pwd) <= 6:
i_pwdLength = 2
elif len(pwd) > 6 and len(pwd) <= 9:
i_pwdLength = 3
elif len(pwd) > 9:
i_pwdLength = 4
if re.search(r'[w]',pwd) and re.search(r'[x]',pwd) and re.search(r'[y]',pwd) and re.search(r'[z]',pwd):
i_pwdChar = 4
elif re.search(r'[w]',pwd) and re.search(r'[x]',pwd) and re.search(r'[y]',pwd):
i_pwdChar = 3
elif re.search(r'[z]',pwd) and re.search(r'[x]',pwd) and re.search(r'[y]',pwd):
i_pwdChar = 3
elif re.search(r'[w]',pwd) and re.search(r'[z]',pwd) and re.search(r'[y]',pwd):
i_pwdChar = 3
elif re.search(r'[w]',pwd) and re.search(r'[x]',pwd) and re.search(r'[y]',pwd) and re.search(r'[z]',pwd):
i_pwdChar = 4
elif re.search(r'[x]',pwd) and re.search(r'[w]',pwd): # This section checks the password for any
i_pwdChar = 2
elif re.search(r'[x]',pwd) and re.search(r'[y]',pwd): # Combination of the letters w,x,y and z.
i_pwdChar = 2
elif re.search(r'[x]',pwd) and re.search(r'[z]',pwd): # I could not find a way to compress these
i_pwdChar = 2
elif re.search(r'[w]',pwd) and re.search(r'[y]',pwd): # Lines so i left them as is as i thought
i_pwdChar = 2
elif re.search(r'[w]',pwd) and re.search(r'[z]',pwd): # That it looked neater
i_pwdChar = 2
elif re.search(r'[y]',pwd) and re.search(r'[z]',pwd):
i_pwdChar = 2
elif re.search(r'[x]',pwd):
i_pwdChar = 1
elif re.search(r'[w]',pwd):
i_pwdChar = 1
elif re.search(r'[y]',pwd):
i_pwdChar = 1
elif re.search(r'[z]',pwd):
i_pwdChar = 1
else:
i_pwdChar = 0
if (len([l for l in pwd if l.isdigit()])) == 0: # This code checks how many integers are included
i_pwdInt = 0
elif (len([l for l in pwd if l.isdigit()])) >= 1 and (len([l for l in pwd if l.isdigit()])) < 3: # In the password, and assigns a number to the
i_pwdInt = 1
elif (len([l for l in pwd if l.isdigit()])) >= 3 and (len([l for l in pwd if l.isdigit()])) < 5: # Variable i_pwdInt accordingly
i_pwdInt = 2
elif (len([l for l in pwd if l.isdigit()])) >=5 and (len([l for l in pwd if l.isdigit()])) <7:
i_pwdInt = 3
elif (len([l for l in pwd if l.isdigit()])) >=7:
i_pwdInt = 4
i_pwdStrength = i_pwdLength + i_pwdChar + i_pwdInt # this determines the passwords overall strength
if i_pwdStrength > 0 and i_pwdStrength <= 4 :
print("This password is bad")
elif i_pwdStrength > 4 and i_pwdStrength <= 8:
print("This password is OK")
elif i_pwdStrength > 8 and i_pwdStrength <= 11:
print("this password is good")
elif i_pwdStrength == 12:
print("this password is the best!!")
attempts = attempts + 1