试图获得列数的个别计数

Question

eid  name
1   john
2    pal
3   mike
4   michel

id eid   mobile     address
1   1   9640253265
2   2   9632587412  hellpp
3   3               poplop
4   4   9638523690           
5   1   9632589632
6   2                addr

如何获得以下输出

name   mobilecount  addresscount
john   2                0
pal    1                2
mike   0                1
michel 1                0

Answer 1

这样的事情：

COUNT

上述查询取决于NULL不计算swift值的函数。

Answer 2

也许这会有所帮助。

select name,SUM(mobilecount) as mobilecount,SUM(addresscount) as addresscount
from
(
  select t1.name,
  case when isnull(t2.mobile,'')<>'' then count(mobile) else 0 end as     
  mobilecount,
  case when isnull(t2.address,'')<>'' then count(mobile) else 0 end as     
  addresscount
  from table1 t1,table2 t2
  where t1.eid = t2.eid
  group by t1.name,t2.mobile,t2.address
)employee
group by name order by name