unzip
MATLAB中的unzip()
功能仅提供输入zip文件位置和输出目录位置的功能。有没有办法从zip存档中提取一个文件而不是所有文件?
如果特定文件已知并且它是唯一需要的文件,则会减少提取文件的时间。
答案 0 :(得分:4)
unzip
standard MATLAB function无法做到这一点,但是......让黑客攻击该功能,让它完成所需的工作!
unzip
单文件黑客使用MATLAB的unzip()
和extractArchive()
(从unzip()
调用)中的代码,可以创建自定义函数,仅从zip存档中提取单个文件。
function [] = extractFile(zipFilename, outputDir, outputFile)
% extractFile
% Obtain the entry's output names
outputName = fullfile(outputDir, outputFile);
% Create a stream copier to copy files.
streamCopier = ...
com.mathworks.mlwidgets.io.InterruptibleStreamCopier.getInterruptibleStreamCopier;
% Create a Java zipFile object and obtain the entries.
try
% Create a Java file of the Zip filename.
zipJavaFile = java.io.File(zipFilename);
% Create a java ZipFile and validate it.
zipFile = org.apache.tools.zip.ZipFile(zipJavaFile);
% Get entry
entry = zipFile.getEntry(outputFile);
catch exception
if ~isempty(zipFile)
zipFile.close;
end
delete(cleanUpUrl);
error(message('MATLAB:unzip:unvalidZipFile', zipFilename));
end
% Create the Java File output object using the entry's name.
file = java.io.File(outputName);
% If the parent directory of the entry name does not exist, then create it.
parentDir = char(file.getParent.toString);
if ~exist(parentDir, 'dir')
mkdir(parentDir)
end
% Create an output stream
try
fileOutputStream = java.io.FileOutputStream(file);
catch exception
overwriteExistingFile = file.isFile && ~file.canWrite;
if overwriteExistingFile
warning(message('MATLAB:extractArchive:UnableToOverwrite', outputName));
else
warning(message('MATLAB:extractArchive:UnableToCreate', outputName));
end
return
end
% Create an input stream from the API
fileInputStream = zipFile.getInputStream(entry);
% Extract the entry via the output stream.
streamCopier.copyStream(fileInputStream, fileOutputStream);
% Close the output stream.
fileOutputStream.close;
end