我可以在setOnClickListener之外编写fab = (FloatingActionButton)findViewById(R.id.fab);
fab.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
TranslateAnimation animation = new TranslateAnimation(400.0f,200.0f,0.0f,0.0f);
animation.setDuration(5000);
animation.setRepeatCount(1);
animation.setRepeatMode(1);
fab.startAnimation(animation);
}
});
，它可以顺利运行，但我需要在setOnClickListener中编写它。
postAsync = new PostAsync();
postAsync.delegate = this;}
显然写public class Sign_inFragment extends Fragment implements AsyncResponse {
PostAsync postAsync;
String email, password, logInResult;
EditText ev, pv;
Button bv;
@Nullable
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View v = inflater.inflate(R.layout.sign_in_fragment, container, false);
bv = (Button) v.findViewById(R.id.signinButton);
ev = (EditText) v.findViewById(R.id.emailTextView);
pv = (EditText) v.findViewById(R.id.passwordTextView);
bv.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
if (ev.getText() != null && pv.getText() != null) {
email = ev.getText().toString();
password = pv.getText().toString();
postAsync = new PostAsync();
postAsync.delegate = this;//this will not work.
postAsync.execute(email, password);
//Toast.makeText(getActivity().getApplicationContext(), "SIGN IN SUCCESFUL", Toast.LENGTH_LONG).show();
}
}
});
return v;
}
@Override
public void processFinish(String output) {
logInResult = output;
if (logInResult.equals("true") ) {
Intent intent = new Intent(getActivity().getApplicationContext(), SignedInActivity.class);
intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TASK | Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(intent);
} else if(logInResult.equals("false")) {
ev.setError("Invalid Account");
}
}
不起作用。你有什么建议吗？
答案 0 :(得分：1)
在您的情况下，this被视为按钮视图，因为您在button点击方法中使用它。如果你想传递片段，你必须像postAsync.delegate = Sign_inFragment.this那样写，或者如果你想要活动，那么postAsync.delegate = getActivity();