Question

我正在编写一个脚本，检查3个不同的变量并匹配true。但是我需要它只在所有条件匹配时才返回true。现在，如果只有一个或两个条件与我的运算符列表匹配，则返回true。

if [ -z "$VAR3" ] || [ "$VAR1" -ge 10 ] || [ "$VAR2" != "WORKING" ]; then
    echo "app failed "$VAR1" check-ins"
    exit 2

elif [ -n "$VAR3" ] || [ "$VAR1" -le 10 ] || [ "$VAR2" == "WORKING" ]; then
    echo "$VAR3" pid active connection is "$VAR2"
    exit 0
fi

我应该只更换||与＆amp;＆amp; ??

Answer 1

是的，||表示OR逻辑运算符，如果至少有一个运算符为true，则返回true。 &&代表AND逻辑运算符，当且仅当所有运算符都为true

时才会返回true

if [ -z "$VAR3" ] && [ "$VAR1" -ge 10 ] && [ "$VAR2" != "WORKING" ]; then
    echo "app failed "$VAR1" check-ins"
    exit 2

elif [ -n "$VAR3" ] && [ "$VAR1" -le 10 ] && [ "$VAR2" == "WORKING" ];    then
    echo "$VAR3" pid active connection is "$VAR2"
    exit 0
fi

Bash：如果然后匹配多个条件，如果一切都是真的

1 个答案: