我正在开发一个应用程序,其中我有电子邮件编辑文本字段,我在其中进行了一些验证,但是当我输入 jj@gm.cim 之类的电子邮件时它不正确但它是错误的验证是 jj@gmail.com 。
我该怎么做?
这是代码: -
public boolean validation(String mobile,String pass,String email){
if (mobile!=null && mobile.length() >= 7 && mobile.length() <= 15) {
if (pass.length() >= 4 && pass.length() <= 8) {
if (isValidEmail(email)) {
return true;
} else {
m_EmailEditText.setError("Invalid EmailID");
return false;
}
} else {
m_PasswordEditText.setError("password must be between 4 to 8 characters long");
return false;
}
} else {
m_MobileEditText.setError("mobile number must be between 7 to 51 characters long");
return false;
}
}
// This is validation for email……….and link to above code….
private boolean isValidEmail(String email) {
String emailPattern = "^[_A-Za-z0-9-\\+]+(\\.[_A-Za-z0-9-]+)*@"
+ "[A-Za-z0-9-]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$";
Pattern pattern = Pattern.compile(emailPattern);
Matcher matcher = pattern.matcher(email);
return matcher.matches();
}
答案 0 :(得分:0)
如果您想使用正则表达式,请尝试这种方式来获取有效的电子邮件
public static boolean isEmailValid(String email) {
boolean isValid = false;
String expression = "^[\\w\\.-]+@([\\w\\-]+\\.)+[A-Z]{2,4}$";
CharSequence inputStr = email;
Pattern pattern = Pattern.compile(expression, Pattern.CASE_INSENSITIVE);
Matcher matcher = pattern.matcher(inputStr);
if (matcher.matches()) {
isValid = true;
}
return isValid;
}
OR 如果你想使用默认验证,请尝试这种方式
boolean isEmailValid(CharSequence email) {
return android.Util.Patterns.EMAIL_ADDRESS.matcher(email).matches();
}
答案 1 :(得分:0)
您也可以使用,
public class EmailValidator {
private Pattern pattern;
private Matcher matcher;
private static final String EMAIL_PATTERN =
"^[_A-Za-z0-9-\\+]+(\\.[_A-Za-z0-9-]+)*@"
+ "[A-Za-z0-9-]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$";
public EmailValidator() {
pattern = Pattern.compile(EMAIL_PATTERN);
}
/**
* Validate hex with regular expression
*
* @param hex
* hex for validation
* @return true valid hex, false invalid hex
*/
public boolean validate(final String hex) {
matcher = pattern.matcher(hex);
return matcher.matches();
}
}
答案 2 :(得分:0)
验证EmailID的功能
EquipmentNumber
答案 3 :(得分:0)
参考android 模式
它是android inbuild正则表达式方法。
https://developer.android.com/reference/android/util/Patterns.html
public final static boolean isValidEmail(CharSequence target) {
return !TextUtils.isEmpty(target) && android.util.Patterns.EMAIL_ADDRESS.matcher(target).matches();
}
通过此SO链接回答 - https://stackoverflow.com/a/7882950/3879847