架构是:
ACTIVITY_SUPERVISOR(SupervisorID)
OUTDOOR_INSTRUCTOR(InstructorID,InstrName,InstrPhone,SupervisorID)
这是我写的,但它不起作用
SELECT O.InstructorID, O.InstrName, O.SupervisorID, A.SupervisorID, COUNT(*)
FROM Outdoor_instructor O, Activity_supervisor A
INNER JOIN Activity_supervisor A ON A.SupervisorID = O.SupervisorID
GROUP BY SupervisorID O, InstrName O
ORDER BY COUNT(*) DESC
LIMIT 1;
答案 0 :(得分:1)
您的查询中有两个对“Activity_supervisor A”的引用。 您的分组中还应包含更多值
试试这个:
SELECT O.InstructorID, O.InstrName, O.SupervisorID, A.SupervisorID, COUNT(*)
FROM Outdoor_instructor O
INNER JOIN Activity_supervisor A ON A.SupervisorID = O.SupervisorID
WHERE rownum = 1
GROUP BY O.InstructorID, O.InstrName, O.SupervisorID, A.SupervisorID
ORDER BY COUNT(*) DESC