我有一个收集字典值以进行细分的函数,如何将它作为嵌套条目附加到我的主字典?
Dict = {}
def getDetail():
subdict = {}
first_name = input("Enter first name")
if first_name.lower() == 'quit':
return None
else:
last_name = input("Enter last name")
nick_name = input("Enter nickname")
address = input("Enter address")
number = input("Enter phone number")
subdict['nick'] = nick_name
subdict['firstname'] = first_name
subdict['lastname'] = last_name
subdict['address'] = address
subdict['number'] = number
return subdict
我希望结果返回一个嵌套的条目,由['nick']
索引,所以Dict看起来像这样
{'Johnny': {'firstname': 'John', 'lastname': 'Johnson', 'address': '103 Alpine Drive', 'nick':'Johnny', 'number': '021-233-4555'}}
答案 0 :(得分:1)
您可以按照通常的方式进行此操作。
my_dict[key] = value
遵循以下格式:
my_dict = Dict
value = getDetail()
key = "Up to you"
my_dict[key] = value
答案 1 :(得分:1)
所以,你可以:
Dict = {}
def getDetail():
subdict = {}
first_name = input("Enter first name")
if first_name.lower() != 'quit':
last_name = input("Enter last name")
nick_name = input("Enter nickname")
address = input("Enter address")
number = input("Enter phone number")
subdict['nick'] = nick_name
subdict['firstname'] = first_name
subdict['lastname'] = last_name
subdict['address'] = address
subdict['number'] = number
dict[nick_name] = subdict
答案 2 :(得分:1)
或者写,简单和肮脏:
MyDict = {}
def GetDetail():
first_name = raw_input("Enter first name: ")
if first_name.lower() == 'quit':
return None
else:
last_name = raw_input("Enter last name: ")
nick_name = raw_input("Enter nickname: ")
address = raw_input("Enter address: ")
number = raw_input("Enter phone number: ")
return {
'nick':nick_name,
'firstname':first_name,
'lastname':last_name,
'address':address,
'number':number
}
MyDict['Johnny'] = GetDetail()
print MyDict
示例输入和输出:
输入姓氏:Higazi
输入昵称:tameritoke
输入地址:MyHomeStreet
输入电话号码:000-1999
{' Johnny':{' nick':' tameritoke','地址':' MyHomeStreet', '号码':' 000-1999','名字':' Tamer','姓氏':&#39 ; Higazi'}}