我的项目中有这个架构,有时UI线程被阻止,有人可以用下面的代码解释发生了什么。感谢
我正在从xamarin.forms viewmodel
异步进行服务调用以下是流程
查看---> ViewModel --- ClassA ---> ClassB - 从此处拨打服务电话
代码
情景1
public partial class HomePage : ContentPage
{
private HomeVM model;
public HomePage()
{
InitializeComponent();
model = new HomeVM();
model.MainText = ReturnBool().Result;
this.BindingContext = model;
}
public async Task<string> ReturnBool()
{
IsBusy = true;
var r = await new WS().ReturnBool();
IsBusy = false;---------------------------------------Not hitting the breakpoint here
return r;
}
}
public interface IWS
{
Task<string> ReturnBool();
}
public class WS : IWS
{
public Task<string> ReturnBool()
{
return ServiceOperations.ReturnBool();
}
}
internal class ServiceOperations
{
public async static Task<string> ReturnBool()
{
var uri = new Uri(string.Format("http://testmyapi.azurewebsites.net/", string.Empty));
try
{
HttpClient client = new HttpClient();
client.BaseAddress = uri;
HttpResponseMessage response = null;
response = await client.GetAsync("/api/Values/Get");
if (response.IsSuccessStatusCode)
{
var content = await response.Content.ReadAsStringAsync();
string str = JsonConvert.DeserializeObject<string>(content);
return str;
}
else {
return null;
}
}
catch (Exception)
{
return null;
}
}
}
情景2
public partial class HomePage : ContentPage
{
private HomeVM model;
public HomePage()
{
InitializeComponent();
model = new HomeVM();
this.BindingContext = model;
}
}
public class HomeVM : BaseVM
{
private string mainText;
public string MainText
{
get { return mainText; }
set
{
mainText = value;
RaisePropertyChanged("MainText");
}
}
public HomeVM()
{
MainText = ReturnBool().Result;
}
public async Task<string> ReturnBool()
{
IsBusy = true;
var r = await new WS().ReturnBool();
IsBusy = false;---------------------------------------Not hitting the breakpoint here
return r;
}
}
public interface IWS
{
Task<string> ReturnBool();
}
public class WS : IWS
{
public Task<string> ReturnBool()
{
return ServiceOperations.ReturnBool();
}
}
internal class ServiceOperations
{
public async static Task<string> ReturnBool()
{
var uri = new Uri(string.Format("http://testmyapi.azurewebsites.net/", string.Empty));
try
{
HttpClient client = new HttpClient();
client.BaseAddress = uri;
HttpResponseMessage response = null;
response = await client.GetAsync("/api/Values/Get");
if (response.IsSuccessStatusCode)
{
var content = await response.Content.ReadAsStringAsync();
string str = JsonConvert.DeserializeObject<string>(content);
return str;
}
else {
return null;
}
}
catch (Exception)
{
return null;
}
}
}
答案 0 :(得分:2)
您正在使用ReturnBool()。结果在构造函数中。返回调用将阻止您的UI线程。将该代码移动到控制器操作方法而不使用&#34; .Result&#34;部分。确保方法是异步的并始终返回任务。