Question

我有下一个服务：

public void checkAll() {
    Session sess = (Session) em.getDelegate();
    System.out.println("Check 1");
    Query query = sess.createQuery("select distinct t from House t left join fetch Kw k on t.id=k.fkHouse "
            + "left join fetch Kart a on k.id=a.fkKw "
            + "left join fetch Reg r on a.lsk=r.lsk "
            + "left join fetch RegState s on a.lsk=s.lsk "
            + " "
            + "where t.klsk = 187804");
    System.out.println("Check 2");
    List<House> lst =query.list(); 
    for (House o : lst) {
        System.out.println("Check 3");
        for (Kw kw : o.getKw()) {
            for (Kart kart : kw.getLsk()) {
                for (Reg reg : kart.getReg()) {
                    System.out.print("Reg="+reg.getDtReg());    
                    break;
                }
                break;
            }
            break;
        }
        break;
    }
    System.out.println("Check 4");
}

我已经打开了Hibernate的SQL Debug，请看下一步：

Check 1
2393 [main] INFO  org.hibernate.hql.internal.QueryTranslatorFactoryInitiator  - HHH000397: Using ASTQueryTranslatorFactory
Check 2
2547 [main] DEBUG org.hibernate.SQL  - select distinct house0_.ID as ID1_1_, house0_.FK_K_LSK as FK_K_LSK2_1_, house0_.FK_STREET as FK_STREET3_1_ from AR.HOUSE house0_ left outer join AR.KW kw1_ on (house0_.ID=kw1_.FK_HOUSE)left outer join AR.KART kart2_ on (kw1_.ID=kart2_.FK_KW)left outer join PS.REG reg3_ on (kart2_.LSK=reg3_.LSK)left outer join PS.REG_STATE regstate4_ on (kart2_.LSK=regstate4_.LSK) where house0_.FK_K_LSK=187804
Check 3
2609 [main] DEBUG org.hibernate.SQL  - select kw0_.FK_HOUSE as FK_HOUSE3_3_0_, kw0_.ID as ID1_3_0_, kw0_.ID as ID1_3_1_, kw0_.FK_K_LSK as FK_K_LSK2_3_1_, kw0_.FK_HOUSE as FK_HOUSE3_3_1_ from AR.KW kw0_ where kw0_.FK_HOUSE=?
2655 [main] DEBUG org.hibernate.SQL  - select kart0_.FK_KW as FK_KW4_2_0_, kart0_.LSK as LSK1_2_0_, kart0_.LSK as LSK1_2_1_, kart0_.FK_K_LSK as FK_K_LSK2_2_1_, kart0_.FIO as FIO3_2_1_, kart0_.FK_KW as FK_KW4_2_1_ from AR.KART kart0_ where kart0_.FK_KW=?
2657 [main] DEBUG org.hibernate.SQL  - select reg0_.LSK as LSK6_15_0_, reg0_.ID as ID1_15_0_, reg0_.ID as ID1_15_1_, reg0_.DT_REG as DT_REG2_15_1_, reg0_.DT_REG_TS as DT_REG_TS3_15_1_, reg0_.DT_UNREG as DT_UNREG4_15_1_, reg0_.DT_UNREG_TS as DT_UNREG_TS5_15_1_, reg0_.LSK as LSK6_15_1_, reg0_.FK_PERS as FK_PERS7_15_1_, reg0_.FK_REG_STATUS as FK_REG_STATUS8_15_1_, reg0_.FK_REG_TP as FK_REG_TP9_15_1_ from PS.REG reg0_ where reg0_.LSK=?
Reg=1996-03-12 00:00:00.0Check 4
3382 [main] DEBUG org.hibernate.SQL  - select distinct house0_.ID as ID1_1_, house0_.FK_K_LSK as FK_K_LSK2_1_, house0_.FK_STREET as FK_STREET3_1_ from AR.HOUSE house0_ left outer join AR.KW kw1_ on (house0_.ID=kw1_.FK_HOUSE)left outer join AR.KART kart2_ on (kw1_.ID=kart2_.FK_KW)left outer join PS.REG reg3_ on (kart2_.LSK=reg3_.LSK)left outer join PS.REG_STATE regstate4_ on (kart2_.LSK=regstate4_.LSK) where house0_.FK_K_LSK=187804

点＃34;检查1＆＃34;我看到带有连接的SQL，它很好，但为什么要点＃34;检查3＆＃34;我看到奇怪的SQL，再次击中基地？

我强制hibernate使用＆＃34; left join fetch＆＃34;加载所有孩子。在点'＃34;检查1＆＃34;，但是为什么它需要再次从数据库中检索孩子？

请帮助我，可能是我需要改变获取子实体的方法吗？可能是我必须解决的Hibernate N + 1问题？

Answer 1

是的，您遇到了"N+1" select问题。

要避免N+1 select问题，请确保您加入获取与House Entity特别是One-One关联相关的所有关联。

HQL也应该像下面的示例一样编写，

 SELECT employee FROM Employee employee  LEFT JOIN FETCH employee.employer

请仔细阅读以下HQL文档：

https://docs.jboss.org/hibernate/orm/3.3/reference/en/html/queryhql.html#queryhql-from

Hibernate左连接总是打到基地

1 个答案: