spyne SOAP Web服务中的多个名称空间

时间:2016-05-24 17:09:38

标签: python soap spyne

我正在尝试使用Spyne框架在python3中托管SOAP服务,这个代码部分代码:

class HelloWorldService(ServiceBase):
    @srpc(Unicode, Integer, _returns=Iterable(Unicode))
    def say_hello(name, times):
        for i in range(times):
            yield 'Hello, %s' % name
application = Application([HelloWorldService],
    tns='spyne.examples.hello',
    in_protocol=Soap11(),
    out_protocol=Soap11()
)
if __name__ == '__main__':
    # You can use any Wsgi server. Here, we chose
    # Python's built-in wsgi server but you're not
    # supposed to use it in production.
    from wsgiref.simple_server import make_server
    wsgi_app = WsgiApplication(application)
    server = make_server('0.0.0.0', 8000, wsgi_app)
    server.serve_forever()

它正在运行,但它只使用一个命名空间。

TNS = 'spyne.examples.hello'

我可以在这一行中定义多个服务:

application = Application([HelloWorldService, OtherService1, OtherService2]

但是可以为每个服务定义不同的命名空间吗?这样的事情不起作用:

tns=['spyne.examples.hello', 'http://other.service1', 'http://other.service2']

1 个答案:

答案 0 :(得分:2)

您可以使用WsgiMounter课程。

from spyne.util.wsgi_wrapper import WsgiMounter

app1 = Application([SomeService], tns=namespace1,
    in_protocol=Soap11(), out_protocol=Soap11())
app2 = Application([SomeOtherService], tns=namespace2,
    in_protocol=Soap11(), out_protocol=Soap11())
wsgi_mounter = WsgiMounter({
    'app1': app1,
    'app2': app2,
})

然后,在代码中传递wsgi_mounter对象而不是wsgi_app:

if __name__ == '__main__':
    from wsgiref.simple_server import make_server
    wsgi_mounter = WsgiMounter({
        'app1': app1,
        'app2': app2, 
    })
    server = make_server('0.0.0.0', 8000, wsgi_mounter)
    server.serve_forever()