Question

我有一个这样的清单：

[[['(0,1,2)','(3,4,5)'],['(5,6,7)','(9,4,2)']],[['(0,1,2)','(3,4,5)'],['(5,6,7)','(9,4,2)']]]

我想得到类似的东西：

[[[[0,1,2],[3,4,5]],[[5,6,7],[9,4,2]]],[[[0,1,2],[3,4,5]],[[5,6,7],[9,4,2]]]

我尝试过字符串理解，重新模块，拆分，剥离但似乎没有工作。谢谢！

Answer 1

递归似乎很简单：

l = [[['(0,1,2)','(3,4,5)'],['(5,6,7)','(9,4,2)']],[['(0,1,2)','(3,4,5)'],['(5,6,7)','(9,4,2)']]]

def convert(x):
    if isinstance(x, list):
        return [convert(y) for y in x]
    else:
        return [int(y) for y in x.strip('()').split(',')]

convert(l) # [[[[0, 1, 2], [3, 4, 5]], [[5, 6, 7], [9, 4, 2]]], [[[0, 1, 2], [3, 4, 5]], [[5, 6, 7], [9, 4, 2]]]]

Answer 2

如果您想查看嵌套列表推导中的内容

startList = [[['(0,1,2)','(3,4,5)'],['(5,6,7)','(9,4,2)']],[['(0,1,2)','(3,4,5)'],['(5,6,7)','(9,4,2)']]]
new = [[[[int(x) for x in moreSub.strip("()").split(",")] for moreSub in subitem] for subitem in item] for item in startList]
print(new)

如何在Python列表中的字符串中创建数字列表

2 个答案: