Question

我有presentation表包含：

ID     DAY         START       END      STARTDATE       ENDDATE
622   Monday     12:00:00    02:00:00   01-05-2016     04-06-2016 
623   Tuesday    12:00:00    02:00:00   01-05-2016     04-06-2016 
624   Wednesday  08:00:00    10:00:00   01-05-2016     04-06-2016 
625   Thursday   10:00:00    12:00:00   01-05-2016     04-06-2016

我想列出从STARTDATE到ENDDATE的所有可能日期。我尝试了一个有效的查询，除了它将列出每个ID的所有可能日期。我可能只需要一个ID，因为所有行基本上都有相同的日期。

查询：

select 
  A.PRESENTATIONID,
  A.PRESENTATIONDATESTART+delta dt
from 
  PRESENTATION A, 
  (
     select level-1 as delta 
     from dual 
     connect by level-1 <= (
       select max(PRESENTATIONDATEEND- PRESENTATIONDATESTART) from PRESENTATION
     )
  )
where A.PRESENTATIONDATESTART+delta <= A.PRESENTATIONDATEEND
order by 1,2;

结果：

622 01-05-2016 12:00:00 //startdate
.....
622 03-06-2016 12:00:00
622 04-06-2016 12:00:00 //enddate
.....
625 04-06-2016 12:00:00

结果很乏味！

我想仅列出日期存储在presentation表格中的可能日期。例如，在presentation表中，日期是星期一，星期二，星期三和星期四。可能的结果将是：

MONDAY
02-05-2016 12:00:00
09-05-2016 12:00:00
16-05-2016 12:00:00
23-05-2016 12:00:00
30-05-2016 12:00:00

TUESDAY
03-05-2016 12:00:00
10-05-2016 12:00:00
17-05-2016 12:00:00
24-05-2016 12:00:00
31-05-2016 12:00:00
.... until THURSDAY

在解释的路上，在这个问题上我想排除星期五，星期六和星期日的日期。有可能吗？

更新

新查询：

select 
  A.PRESENTATIONID,
  A.PRESENTATIONDAY,
  A.PRESENTATIONDATESTART+delta dt
from 
  PRESENTATION A, 
  (
     select level-1 as delta 
     from dual 
     connect by level-1 <= (
       select max(PRESENTATIONDATEEND- PRESENTATIONDATESTART) from PRESENTATION
     )
  )
where A.PRESENTATIONDATESTART+delta <= A.PRESENTATIONDATEEND
and
  a.presentationday = trim(to_char(A.PRESENTATIONDATESTART+delta, 'Day'))
order by 1,2,3;

结果：

622 Monday  02-05-2016 12:00:00
622 Monday  09-05-2016 12:00:00
622 Monday  16-05-2016 12:00:00
622 Monday  23-05-2016 12:00:00
622 Monday  30-05-2016 12:00:00
623 Tuesday 03-05-2016 12:00:00
623 Tuesday 10-05-2016 12:00:00
623 Tuesday 17-05-2016 12:00:00
623 Tuesday 24-05-2016 12:00:00
623 Tuesday 31-05-2016 12:00:00
624 Wednesday   04-05-2016 12:00:00
624 Wednesday   11-05-2016 12:00:00
624 Wednesday   18-05-2016 12:00:00
624 Wednesday   25-05-2016 12:00:00
624 Wednesday   01-06-2016 12:00:00
625 Thursday    05-05-2016 12:00:00
625 Thursday    12-05-2016 12:00:00
625 Thursday    19-05-2016 12:00:00
625 Thursday    26-05-2016 12:00:00
625 Thursday    02-06-2016 12:00:00

您可以查看日历以查看日期和日期是否匹配：D再次感谢@dcieslak！

Answer 1

添加到您的查询：

 and
  a.day = trim(to_char(A.PRESENTATIONDATESTART+delta, 'Day'))

它会删除与您的DAY列不相等的日期。 trim对于'Day'很重要，因为我们想要摆脱前导和尾随空格。

根据特定日期获取所有可能日期的列表[oracle 11g]

1 个答案: