用空写程序覆盖数组

时间:2016-05-22 22:49:47

标签: java arrays null

对于学校的项目(java简介),我们必须使用数组创建一个程序。我决定制作一个存储登录的登录程序。除了删除项目外,它完美无缺。这是我的代码

    public void delete() throws FileNotFoundException{
    int p;
    c.clear();
    c.print("Please enter a website to delete it's login info: ");
    String delete_name = c.readLine();
    Boolean found = false;

    // Search for the search key, and display the matching elements
    c.println("Searching for " + delete_name + "...");
    for (int i = 0; i < pass.length; i++)
        if (pass[i][0].equals(delete_name)) {
            c.println("Deleting login for " + pass[i][0]);


            String new_array[][] = new String[pass.length - 1][3];
            //remove an element
            for (int w = 0; i < new_array.length; i++)
                for (int j = 0; j <= 2; j++) {
                    p = w;
                    if (i >= p) {
                        new_array[w][j] = pass[w + 1][j];

                    } else {
                        new_array[w][j] = pass[w][j];


                    }
                }

            found = true;
            pass = new_array;
        }

    if (found == false) {
        c.println("No luck! " + delete_name + " wasn't found, please try again.");
        delete();
    }
        fileWriter();

}

当它写入文件时,应该删除的部分之后的任何内容都会更改为&#34; null&#34;。

对不起,如果格式很糟糕,我只是从java开始:)非常感谢任何帮助,谢谢!

1 个答案:

答案 0 :(得分:0)

在Java中删除2D数组的行时,可以使用此快捷方式(不需要for-loops

List<String[]> tempArr = new ArrayList<String[]>(Arrays.asList(pass));
//Remove row at index of "delete_name":
for(int i = 0; i < pass.length; i++){
  if(pass[i][0].equals(delete_name)){
    tempArr.remove(i);
  }
}
String[][] new_array = tempArr.toArray(new String[][]{});

但是,此解决方案仅在您只删除列表中的一个对象时才有效。我建议调查“iterators”以使此解决方案更好。

编辑:

以下是iterator

的示例
    String[][] pass = new String[][]{{"Name","data1","data2"}};
    List<String[]> tempArr = new ArrayList<String[]>(Arrays.asList(pass));
    for (Iterator<String[]> iterator = tempArr.iterator(); iterator.hasNext();) {
        String id = iterator.next()[0];
        if (id.equals(delete_name)){
            iterator.remove();
        }
    }