您好我正在尝试使用4个字段进行搜索,但是当我进行搜索时,其中一些可能为空。这就是我选择queryDsl的原因。 这是我的pom.xml
<dependency>
<groupId>com.mysema.querydsl</groupId>
<artifactId>querydsl-jpa</artifactId>
</dependency>
我制作了ClientPredicate.java
final class ClientPredicates {
private ClientPredicates() {
}
static Predicate firstnameOrLastnameOrCinOrPhoneNberContainsIgnoreCase(String searchTerm) {
if (searchTerm == null || searchTerm.isEmpty()) {
return (Predicate) QClient.client.isNotNull();
} else {
return (Predicate) QClient.client.firstname.containsIgnoreCase(searchTerm)
.or(QClient.client.lastname.containsIgnoreCase(searchTerm)).or
(QClient.client.cin.containsIgnoreCase(searchTerm)).or(QClient.client.phoneNber.containsIgnoreCase(searchTerm));
}
}
}
QClient.java
@Generated("com.mysema.query.codegen.EntitySerializer")
public class QClient extends EntityPathBase<Client> {
private static final long serialVersionUID = -797939782L;
public static final QClient client = new QClient("client");
public final StringPath createdByUser = createString("createdByUser");
public final DateTimePath<java.time.ZonedDateTime> creationTime = createDateTime("creationTime", java.time.ZonedDateTime.class);
public final StringPath firstname = createString("firstname");
public final StringPath lastname = createString("lastname");
public final StringPath cin = createString("cin");
public final StringPath phoneNber = createString("phoneNber");
public final NumberPath<Long> id = createNumber("id", Long.class);
public final DateTimePath<java.time.ZonedDateTime> modificationTime = createDateTime("modificationTime", java.time.ZonedDateTime.class);
public final StringPath modifiedByUser = createString("modifiedByUser");
public final NumberPath<Long> version = createNumber("version", Long.class);
public QClient(String variable) {
super(Client.class, forVariable(variable));
}
public QClient(Path<Client> path) {
super(path.getType(), path.getMetadata());
}
public QClient(PathMetadata<?> metadata) {
super(Client.class, metadata);
}
}
在我的控制器中我有这段代码:
@RequestMapping(value = "/seekClient", method = RequestMethod.POST, headers = "Accept=application/json")
public @ResponseBody List<Client> seekClient(@RequestBody Client client) {
Predicate firstnameAndLastnameAndCinAndPhoneNberAre = QClient.client.firstname.eq(client.getFirstname())
.and(QClient.client.lastname.eq(client.getLastname()));
System.out.println("*************************** "+firstnameAndLastnameAndCinAndPhoneNberAre);
List<Client> list = (List<Client>) clientRepository.findAll(firstnameAndLastnameAndCinAndPhoneNberAre);
return list;
}
问题是我每次发送一个空字段时都会收到nullPointerException。 请帮忙。我被阻止了几个小时
答案 0 :(得分:0)
我希望“发送一个空字段”意味着在你的控制器中参数为null。因此,访问它的方法将引发异常。在控制器中添加一个空检查,你应该很好。