在设置键盘快捷键以在Linux中打开 xonsh 时，我应该将其作为命令放置？
放
xonsh
因为命令似乎不起作用，但
subl
启动崇高。
（我正在使用Kali 2.0）。
答案 0 :(得分：0)
Xonsh应该在您的终端内运行。我在基本操作系统中运行它，命令将读取package com.foo.bar;
import org.apache.felix.scr.annotations.sling.SlingServlet;
import org.apache.sling.api.SlingHttpServletRequest;
import org.apache.sling.api.SlingHttpServletResponse;
import org.apache.sling.api.resource.Resource;
import org.apache.sling.api.resource.ResourceResolver;
import org.apache.sling.api.servlets.SlingSafeMethodsServlet;
import javax.jcr.query.Query;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;
import java.io.PrintWriter;
import java.util.Iterator;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
@SlingServlet(paths={"/bin/deletedsstore"})
public class DeleteDSStoreServlet extends SlingSafeMethodsServlet {
private static final long serialVersionUID = 1L;
private static final Logger log = LoggerFactory.getLogger(DeleteDSStoreServlet.class);
private static final String SQL2_QUERY = "SELECT * FROM [nt:base] AS s WHERE ISDESCENDANTNODE([/content]) and NAME() = '.DS_Store'";
private static final int SAVE_THRESHOLD = 100;
@Override
protected void doGet(SlingHttpServletRequest request, SlingHttpServletResponse response) throws ServletException, IOException {
ResourceResolver resolver = request.getResourceResolver();
Iterator<Resource> resources = resolver.findResources(SQL2_QUERY, Query.JCR_SQL2);
int deleted = 0;
while (resources.hasNext()) {
Resource resource = resources.next();
String path = resource.getPath();
resolver.delete(resource);
log.info("Deleted node: " + path);
deleted++;
if (deleted % SAVE_THRESHOLD == 0) {
resolver.commit();
}
}
if (resolver.hasChanges()) {
resolver.commit();
}
response.setStatus(HttpServletResponse.SC_OK);
PrintWriter out = response.getWriter();
out.write("Deleted " + deleted + " .DS_Store nodes");
}
}
。找出您正在使用的终端作为标准，并编辑上面的命令。