需要你的帮助,我在访问此网址时收到HTTP状态404
localhost:8080/SurakartaSmart/adm-ser/view-all
下面是我的控制器
@Controller
@RequestMapping("/adm-ser")
public class adminController {
@Autowired
adminService serv;
@RequestMapping(value="/view-all", method=RequestMethod.GET)
public @ResponseBody List<adminModel>viewall()throws Exception{
List<adminModel>data = null;
try{
data = serv.viewall();
}catch(Exception e){
e.getMessage();
}
return data;
}
}
的web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" id="WebApp_ID" version="3.1">
<display-name>surakarta-smar</display-name>
<servlet>
<servlet-name>mvc-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-config.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>mvc-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
我需要改进哪个错误?