Question

我想在SQL Server中找到包含两个特定单独列的所有表。

第一列名称是“LIKE'％A％'”（意思是它包含子串“A”），第二列名称是“LIKE'％B％'”（意思是它包含子串“B”）

我写了以下查询，我想检查一下它的正确性：

SELECT s.TABLE_NAME 
FROM (SELECT COLUMN_NAME, TABLE_NAME 
    FROM INFORMATION_SCHEMA.COLUMNS 
    WHERE COLUMN_NAME LIKE '%A%'
    UNION
    SELECT COLUMN_NAME, TABLE_NAME 
    FROM INFORMATION_SCHEMA.COLUMNS 
    WHERE COLUMN_NAME LIKE '%B%') s
WHERE EXISTS (SELECT COLUMN_NAME, s.TABLE_NAME 
              FROM INFORMATION_SCHEMA.COLUMNS
              WHERE COLUMN_NAME LIKE '%A%')
AND EXISTS (SELECT COLUMN_NAME, s.TABLE_NAME
            FROM INFORMATION_SCHEMA.COLUMNS
            WHERE COLUMN_NAME LIKE '%B%');

Answer 1

这应该更容易：

SELECT s.TABLE_NAME 
FROM INFORMATION_SCHEMA.TABLES AS s
WHERE s.TABLE_TYPE='BASE TABLE'
AND EXISTS (SELECT 1 
              FROM INFORMATION_SCHEMA.COLUMNS
              WHERE TABLE_NAME=s.TABLE_NAME AND COLUMN_NAME LIKE '%A%')
AND EXISTS (SELECT 1
            FROM INFORMATION_SCHEMA.COLUMNS
            WHERE TABLE_NAME=s.TABLE_NAME AND COLUMN_NAME LIKE '%B%');

更新

使用此代码，您会发现所有列都将标准作为列表...

SELECT s.TABLE_NAME,listA,listB
FROM INFORMATION_SCHEMA.TABLES AS s
CROSS APPLY (SELECT STUFF(
             (
                 SELECT ', ' + COLUMN_NAME 
                 FROM INFORMATION_SCHEMA.COLUMNS
                 WHERE TABLE_NAME=s.TABLE_NAME AND COLUMN_NAME LIKE '%med%'
                 ORDER BY ORDINAL_POSITION
                 FOR XML PATH('')
             ),1,2,'')
             ) AS columnsWithA(listA)
CROSS APPLY (SELECT STUFF(
             (
                 SELECT ', ' + COLUMN_NAME 
                 FROM INFORMATION_SCHEMA.COLUMNS
                 WHERE TABLE_NAME=s.TABLE_NAME AND COLUMN_NAME LIKE 'kli%'
                 ORDER BY ORDINAL_POSITION
                 FOR XML PATH('')
             ),1,2,'')
             ) AS columnsWithB(listB)
WHERE s.TABLE_TYPE='BASE TABLE'
  AND listA IS NOT NULL AND listB IS NOT NULL

更新2

使用最终AND listA<>listB AND CHARINDEX(',',listA)=0，只要只有一列（=＆gt;无逗号），您就会排除相同的listA和listB

Answer 2

将逻辑设定为救援！

SELECT DISTINCT TABLE_NAME 
FROM INFORMATION_SCHEMA.COLUMNS AS c
WHERE COLUMN_NAME LIKE '%A%' 
AND COLUMN_NAME NOT LIKE '%B%'

INTERSECT

SELECT DISTINCT TABLE_NAME 
FROM INFORMATION_SCHEMA.COLUMNS AS c
WHERE COLUMN_NAME LIKE '%B%' 
AND COLUMN_NAME NOT LIKE '%A%'

已更新，可相互排除双重匹配。 删除了TABLE架构上的内部联接

Answer 3

一种方法只使用聚合和having：

SELECT TABLE_NAME 
FROM INFORMATION_SCHEMA.COLUMNS 
GROPU BY TABLE_NAME
HAVING SUM(CASE WHEN COLUMN_NAME LIKE '%A%' THEN 1 ELSE 0 END) > 0 AND
       SUM(CASE WHEN COLUMN_NAME LIKE '%B%' THEN 1 ELSE 0 END) > 0;

如有必要，您可以使用联接回INFORMATION_SCHEMA.COLUMNS来获取列名称 - 尽管这不是您的实际问题。

在SQL Server

3 个答案:

更新

更新2