在此程序中,如果您选择项目代码,它将显示3个字段并要求更新,如果您更新它将更新记录。直到这个程序都没问题。
我添加了一个条件,如果用户按 Ctrl + D 它要求删除问题是或否,它是肯定你更新的字段应该是空白否则做什么都没试过,但我无法做到。
/*Sample Item master Maintenance Program*/
/* DISPLAY TITLE */
{us/mf/mfdtitle.i "3+ "}
def var l_qad like pt__qad13.
def var l_draw like pt_draw.
def var l_group like pt_group.
def var ans as logical no-undo.
form
pt_part colon 25
with frame a side-labels width 80.
/* SET EXTERNAL LABELS */
setFrameLabels(frame a:handle).
form
"Enter the Value of" l_qad colon 30 skip(1)
"Enter the Value of" l_draw colon 30 skip(1)
"Enter the Value of" l_group colon 30 skip(1)
with frame b side-labels width 80.
setFrameLabels(frame b:handle).
view frame a.
repeat with frame a:
prompt-for pt_part
editing:
/* FIND NEXT/PREVIOUS RECORD */
{us/mf/mfnp.i pt_mstr pt_part "pt_mstr.pt_domain = global_domain and pt_part" pt_part pt_part pt_part }
if recno <> ? then
do:
display pt_part.
end.
end.
for first pt_mstr exclusive-lock where pt_domain = global_domain and pt_part = input pt_part:
assign l_qad= pt__qad13
l_draw= pt_draw
l_group= pt_group.
disp l_qad l_draw l_group with frame b.
update l_qad l_draw l_group with frame b.
assign pt__qad13 = input l_qad
pt_draw = input l_draw
pt_group = input l_group.
end.
hide frame b.
on CTRL-D ANYWHERE
do:
message "Please confirm delete" view-as alert-box question buttons yes-no update ans as logical.
if ans= true then
message "yes".
assign pt__qad13 = ""
pt_draw = ""
pt_group = "".
else
message "no".
end.
end.
答案 0 :(得分:1)
您的触发器需要在代码中提前放置。
看看这个基本示例,您可以尝试评论/取消注释两个触发器,看看会发生什么:
DEFINE VARIABLE cUpdate AS CHARACTER NO-UNDO.
/* Placing the trigger here works! */
ON 'ctrl-d':U ANYWHERE DO:
MESSAGE "You rang sir?" VIEW-AS ALERT-BOX INFORMATION TITLE "Early trigger".
RETURN.
END.
UPDATE cUpdate.
/* Placing the trigger here wont work! */
/*
ON 'ctrl-d':U ANYWHERE DO:
MESSAGE "You rang sir?" VIEW-AS ALERT-BOX INFORMATION TITLE "Late trigger".
RETURN.
END.
*/
进度仅在编译时传递一次代码。因此,它永远不会知道你现在所处的任何“前方”(使用FUNCTIONS声明FORWARD是一个例外)。