Question

我有一个很长的MYSQL查询，它从四个表中选择一个总数，但其中一个子查询返回多行并导致错误。
这是我的疑问：

select created,  
    (select coalesce(sum(equal_to_dollar), 0) from capitals group by created )  as capital,

    (select coalesce(sum(incoming), 0) - coalesce(sum(outgoing), 0) from transactions where currency = 'دالر') +
    (select coalesce(sum(equal_to_dollar), 0) from transactions where incoming != 0 ) -
    (select coalesce(sum(equal_to_dollar), 0) from transactions where outgoing != 0 ) as total_transaction,

    (select coalesce(sum(incoming), 0) - coalesce(sum(outgoing), 0) from temporary_clients where currency = 'دالر') +
    (select coalesce(sum(equal_to_dollar), 0) from temporary_clients where incoming != 0 ) -
    (select coalesce(sum(equal_to_dollar), 0) from temporary_clients where outgoing != 0 ) as total_temp_client,

    (select coalesce(sum(outgoing), 0) - coalesce(sum(incoming), 0) from money_transmission where currency = 'دالر') +
    (select coalesce(sum(equal_to_dollar), 0) from money_transmission where outgoing != 0 ) -
    (select coalesce(sum(equal_to_dollar), 0) from money_transmission where incoming != 0 ) as total_transmission,

    (select coalesce(total_transaction + total_temp_client + total_transmission, 0)) as total,

    (select capital - abs(coalesce(total_transaction + total_temp_client + total_transmission, 0))) as result
    from capitals group by created

在此查询中，第一个选择created会返回多个值，而以as capital结尾的第一个子查询也会返回多个值。
此查询应返回资本计算结果，其中包含数据库中每个日期的其他三个表的总和我检查了许多具有相同错误的问题，所有问题都在IN条款中使用了inner join或where，但我认为我的情况有所不同，我不知道该怎么做。
如果您有任何想法我可以帮助我如何解决这个问题谢谢你:)）

Answer 1

尝试类似：

select created,c.sum_dollars

    (select coalesce(sum(incoming), 0) - coalesce(sum(outgoing), 0) from transactions where currency = 'دالر') +
    (select coalesce(sum(equal_to_dollar), 0) from transactions where incoming != 0 ) -
    (select coalesce(sum(equal_to_dollar), 0) from transactions where outgoing != 0 ) as total_transaction,

    (select coalesce(sum(incoming), 0) - coalesce(sum(outgoing), 0) from temporary_clients where currency = 'دالر') +
    (select coalesce(sum(equal_to_dollar), 0) from temporary_clients where incoming != 0 ) -
    (select coalesce(sum(equal_to_dollar), 0) from temporary_clients where outgoing != 0 ) as total_temp_client,

    (select coalesce(sum(outgoing), 0) - coalesce(sum(incoming), 0) from money_transmission where currency = 'دالر') +
    (select coalesce(sum(equal_to_dollar), 0) from money_transmission where outgoing != 0 ) -
    (select coalesce(sum(equal_to_dollar), 0) from money_transmission where incoming != 0 ) as total_transmission,

    (select coalesce(total_transaction + total_temp_client + total_transmission, 0)) as total,

    (select capital - abs(coalesce(total_transaction + total_temp_client + total_transmission, 0))) as result
    from capitals
 JOIN (select coalesce(sum(equal_to_dollar), 0) as sum_dollars, created from capitals group by   created )  c ON capitals.created = c.created
 group by created

我无法真正测试因为我不知道你的数据库架构。无论如何你应该加入那些结果集。

如何解决子查询在多个选择中返回多于1行的错误

1 个答案: