Question

我正在尝试对我的项目使用简单的加密/解密（treyfer），但是没有可用的解密参考实现。我得到的（基于维基百科的实现）是：

uint8_t rotl(uint8_t x) {
  return (x << 1) | (x >> 7);
}

uint8_t rotr(uint8_t x) {
  return (x >> 1) | (x << 7);
}

void encrypt (uint8_t text[8], uint8_t key[8]) {
  int r, i;
  uint8_t t;

  for (r=0; r<NUMROUNDS; r++) {
      text[8] = text[0];
      for (i=0; i<8; i++) {
          text[i+1] = rotl((text[i+1] + sbox[(key[i] + text[i]) % 256]));
      }
      text[0] = text[8];
  }
}

void decrypt (uint8_t text[8], uint8_t key[8]) {
    int r, i;
    uint8_t t;

    for (r=0; r<NUMROUNDS; r++) {
        text[8] = text[0];
        for (i=8; i>=0; --i) {
            text[i+1] = rotr(text[i+1]) - sbox[(key[i] + text[i]) % 256];
        }
        text[0] = text[8];
    }
}


void printhex(uint8_t text[8]) {
    for(int i = 0; i < 8; i++) {
        printf("%02x", text[i]);
    }
}
int main() { 
    char text[8+1] = "AAAAAAAA";
    char key[8+1] = "AAAAAAAA";
    puts("plaintext:");
    printhex(text);
    puts("\nkey:");
    printhex(key);
    puts("\nencrypted:");
    encrypt(text, key);
         printhex(text);
         puts("\ndecrypted:");
        decrypt(text, key);
        printhex(text);
    }

其中Sbox是AES S-box，NUMROUNDS = 128 但是，当我运行这个时，我的明文和解密值得到了截然不同的结果，这表明我的加密或解密是不正确的，但我不太明白。希望我没有错过任何太痛苦的事情。我得到的输出是：

plaintext:
4141414141414141
key:
4141414141414141
encrypted:
658ed27d394127a0
decrypted:
a0460a65d755953f

Answer 1

我认为您的实施基于此：https://en.wikipedia.org/wiki/Treyfer

#include <stdio.h>
#include <string.h>
#include <stdint.h>

#define NUMROUNDS 100

static const uint8_t sbox[256] =   {
  //0     1    2      3     4    5     6     7      8    9     A      B    C     D     E     F
  0x63, 0x7c, 0x77, 0x7b, 0xf2, 0x6b, 0x6f, 0xc5, 0x30, 0x01, 0x67, 0x2b, 0xfe, 0xd7, 0xab, 0x76,
  0xca, 0x82, 0xc9, 0x7d, 0xfa, 0x59, 0x47, 0xf0, 0xad, 0xd4, 0xa2, 0xaf, 0x9c, 0xa4, 0x72, 0xc0,
  0xb7, 0xfd, 0x93, 0x26, 0x36, 0x3f, 0xf7, 0xcc, 0x34, 0xa5, 0xe5, 0xf1, 0x71, 0xd8, 0x31, 0x15,
  0x04, 0xc7, 0x23, 0xc3, 0x18, 0x96, 0x05, 0x9a, 0x07, 0x12, 0x80, 0xe2, 0xeb, 0x27, 0xb2, 0x75,
  0x09, 0x83, 0x2c, 0x1a, 0x1b, 0x6e, 0x5a, 0xa0, 0x52, 0x3b, 0xd6, 0xb3, 0x29, 0xe3, 0x2f, 0x84,
  0x53, 0xd1, 0x00, 0xed, 0x20, 0xfc, 0xb1, 0x5b, 0x6a, 0xcb, 0xbe, 0x39, 0x4a, 0x4c, 0x58, 0xcf,
  0xd0, 0xef, 0xaa, 0xfb, 0x43, 0x4d, 0x33, 0x85, 0x45, 0xf9, 0x02, 0x7f, 0x50, 0x3c, 0x9f, 0xa8,
  0x51, 0xa3, 0x40, 0x8f, 0x92, 0x9d, 0x38, 0xf5, 0xbc, 0xb6, 0xda, 0x21, 0x10, 0xff, 0xf3, 0xd2,
  0xcd, 0x0c, 0x13, 0xec, 0x5f, 0x97, 0x44, 0x17, 0xc4, 0xa7, 0x7e, 0x3d, 0x64, 0x5d, 0x19, 0x73,
  0x60, 0x81, 0x4f, 0xdc, 0x22, 0x2a, 0x90, 0x88, 0x46, 0xee, 0xb8, 0x14, 0xde, 0x5e, 0x0b, 0xdb,
  0xe0, 0x32, 0x3a, 0x0a, 0x49, 0x06, 0x24, 0x5c, 0xc2, 0xd3, 0xac, 0x62, 0x91, 0x95, 0xe4, 0x79,
  0xe7, 0xc8, 0x37, 0x6d, 0x8d, 0xd5, 0x4e, 0xa9, 0x6c, 0x56, 0xf4, 0xea, 0x65, 0x7a, 0xae, 0x08,
  0xba, 0x78, 0x25, 0x2e, 0x1c, 0xa6, 0xb4, 0xc6, 0xe8, 0xdd, 0x74, 0x1f, 0x4b, 0xbd, 0x8b, 0x8a,
  0x70, 0x3e, 0xb5, 0x66, 0x48, 0x03, 0xf6, 0x0e, 0x61, 0x35, 0x57, 0xb9, 0x86, 0xc1, 0x1d, 0x9e,
  0xe1, 0xf8, 0x98, 0x11, 0x69, 0xd9, 0x8e, 0x94, 0x9b, 0x1e, 0x87, 0xe9, 0xce, 0x55, 0x28, 0xdf,
  0x8c, 0xa1, 0x89, 0x0d, 0xbf, 0xe6, 0x42, 0x68, 0x41, 0x99, 0x2d, 0x0f, 0xb0, 0x54, 0xbb, 0x16 };

void treyfer_encrypt(uint8_t text[8], uint8_t const key[8])
{
    unsigned i;
    uint8_t t = text[0];
    for (i = 0; i < 8*NUMROUNDS; i++) {
        t += key[i%8];
        t = sbox[t] + text[(i+1)%8];
        text[(i+1) % 8] = t = (t << 1) | (t >> 7);        /* Rotate left 1 bit */
    }
}

void encrypt(uint8_t text[8], uint8_t const key[8])
{
    unsigned int i = 0;
    unsigned int j = 0;
    uint8_t t = 0;

    t = text[0];

    for (j = 0; j < NUMROUNDS; j++)
    {
        for (i = 0; i < 8; i++)
        {
            t = t + key[i];
            t = sbox[t] + text[(i + 1) % 8];
            t = (t << 1) | (t >> 7);
            text[(i + 1) % 8] = t;
        }
    }
}

void decrypt(uint8_t text[8], uint8_t const key[8])
{
    int i = 0;
    int j = 0;
    uint8_t top = 0;
    uint8_t bottom = 0;

    for (j = 0; j < NUMROUNDS; j++)
    {
        for (i = 7; i >= 0; i--)
        {
            top = text[i] + key[i];
            top = sbox[top];

            bottom = text[(i + 1) % 8];
            bottom = (bottom >> 1) | (bottom << 7);

            text[(i + 1) % 8] = bottom - top;
        }
    }
}


void printhex(uint8_t text[8]) {
    int i;
    for(i = 0; i < 8; i++) {
        printf("%02x", text[i]);
    }
}
int main() {
    uint8_t text[8] = "AAAAAAAA";
    uint8_t text2[8] = "AAAAAAAA";
    uint8_t key[8] = "AAAAAAAA";

    puts("plaintext:");
    printhex(text);

    puts("\nkey:");
    printhex(key);

    puts("\n\nref encrypted:");
    treyfer_encrypt(text, key);
    printhex(text);

    puts("\n\nencrypted:");
    encrypt(text2, key);
    printhex(text2);

    puts("\n\ndecrypted:");
    decrypt(text2, key);
    printhex(text2);
    puts("\n");
}

结果

plaintext:
4141414141414141
key:
4141414141414141

ref encrypted:
cc3121ccab578d93

encrypted:
cc3121ccab578d93

decrypted:
4141414141414141

加密实施 - 令人困惑的结果

1 个答案: