我已经研究了好几天了,我找不到导致内存泄漏的原因?我是C ++的新手,有人可以向我解释我做错了什么。我不断调用pop()直到根节点在析构函数中为null,直到列表为空,这应该在对象上调用delete。
#pragma once
template<typename T>
class LinkList
{
public:
class LinkNode
{
public:
LinkNode() : next(nullptr)
{
}
bool operator!=(LinkNode *a_node)
{
return (this->data != a_node->data);
}
bool operator==(LinkNode *a_node)
{
return (this->data == a_node->data);
}
void operator=(LinkNode *a_node)
{
this->data = a_node->data;
this->next = a_node->next;
}
T data;
LinkNode* next;
};
class LinkIterator
{
public:
LinkIterator(LinkNode* a_root) : node(a_root)
{
}
~LinkIterator()
{
}
T& operator*()
{
return this->node->data;
}
void operator++() //Prefix
{
this->node = this->node->next;
}
void operator++(int) //Postfix
{
this->node = this->node->next;
}
bool operator!=(LinkIterator a_linkIterator)
{
return (node != a_linkIterator.node);
}
bool operator==(LinkIterator a_linkIterator)
{
return (node != a_linkIterator.node);
}
LinkNode* node;
};
LinkList() : size(0), root(nullptr), lastNode(nullptr)
{
}
~LinkList()
{
while (root != nullptr)
{
pop();
}
}
LinkIterator begin()
{
return LinkIterator(root);
}
LinkIterator end()
{
return nullptr;
}
void push(T a_data)
{
LinkNode* node = new LinkNode;
node->data = a_data;
node->next = nullptr;
if (lastNode != nullptr)
{
lastNode->next = node;
lastNode = node;
}
else
{
root = node;
lastNode = node;
}
size++;
}
void pop()
{
if (root->next == nullptr)
{
delete root;
root = nullptr;
}
else
{
LinkNode *prevNode = root;
while (prevNode->next != nullptr && prevNode->next != lastNode)
{
prevNode = prevNode->next;
}
delete lastNode;
prevNode->next = nullptr;
lastNode = prevNode;
}
if (size != 0)
size--;
}
int getSize()
{
return size;
}
void push_front(T a_data)
{
LinkNode *node = new LinkNode;
node->data = a_data;
node->next = nullptr;
if (root != nullptr)
{
node->next = root;
root = node;
}
else
{
root = node;
lastNode = node;
}
size++;
node = nullptr;
}
void pop_front()
{
LinkNode *temp = root;
root = root->next;
delete temp;
if (size != 0)
size--;
}
void clear()
{
root = nullptr;
size = 0;
}
bool empty()
{
return (size == 0);
}
T& front()
{
return root->data;
}
T& back()
{
return lastNode->data;
}
void insert(T a_data, unsigned int index)
{
if (index <= size)
{
LinkNode* position = root;
for (unsigned int i = 0; i < index -1; i++)
{
position = position->next;
}
LinkNode *node = new LinkNode;
node->data = a_data;
node->next = position->next;
position->next = node;
}
else if(size == 0)
{
root->data = a_data;
}
else
{
push(a_data);
}
}
private:
unsigned int size;
LinkNode* root;
LinkNode* lastNode;
};
答案 0 :(得分:1)
我不断调用pop()直到列表为空,这应该调用 删除对象。
除了你在clear()
中没有做任何类似的事情。在自定义链接列表类上调用clear()
将泄漏已分配的所有内存。
如果您的泄漏代码未使用clear()
,则需要修改问题并添加Minimum, Complete, and Verifiable example。