我正在尝试将父级的onChange函数传递给grandChild但是收到错误
var Tablefortask = React.createClass({
getInitialState: function() {
return {data: []};
},
onChange: function (e) {
var employeeId = e.target.value;
alert(employeeId);
},
render: function() {
return (
<div className="border-basic-task col-md-12">
<div className="col-md-12">
<table className="table table-condensed table-bordered table-striped-col " id="table-data">
<thead>
<tr align="center">
<th>Task Name</th>
<th >Standard Discription of Task</th>
<th>Employee Comment</th>
<th >Employee Rating</th>
<th width="30%">Reviewer Comment</th>
<th >Reviewer Rating</th>
</tr>
</thead>
<TablefortaskList data={this.state.data} onChange={this.onChange} />
</table>
</div>
</div>
);
}
});
var TablefortaskList = React.createClass({
render: function() {
var commentNodes = this.props.data.map(function(comment) {
return (
<Addcontenttotable onChange= {this.props.onChange} taskName={comment.taskName} standarDescription={comment.standarDescription} emplComment={comment.emp_comment} empRating={comment.empRating} key={comment.id} reviewComment={comment.review_comment} reviewRating={comment.review_rating} >
</Addcontenttotable>
);
});
return (
<tbody>{commentNodes}</tbody>
);
}
});
var Addcontenttotable = React.createClass({
render: function() {
if(this.props.reviewComment=== "" && this.props.reviewRating === '' ){
return (
<tr><td>{this.props.taskName}</td>
<td>{this.props.standarDescription}</td>
<td>{this.props.emplComment}</td>
<td width="5%">{this.props.empRating}</td>
<td ><textarea
className="form-control"
name="empComment"
placeholder="Employee Comment"
/>
</td>
<td>
<select
className="form-control"
onChange={this.props.onChange}
data-placeholder="Basic Select2 Box" >
<option value="">Option</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
</select>
</td>
</tr>
);
}
else {
return (
<tr><td>{this.props.taskName}</td>
<td>{this.props.standarDescription}</td>
<td>{this.props.emplComment}</td>
<td>{this.props.empRating}</td>
<td>{this.props.reviewComment}</td>
<td>{this.props.reviewRating}</td>
</tr>
);
}
}
});
代码如下
{{1}}
任何见解都将受到赞赏
答案 0 :(得分:1)
每当你得到一个&#39; 这个&#39;错误,你有第一个解决方案!
为您的班级定义构造函数,如下所示:
var variable = React.createClass({
ctor: function(){
this = self;
},
func1: function(){
//your code
this.anything//error
self.anything//solved
},
func2: function(){
//your code
this.anything//error
self.anything//solved
},
func3: function(){
//your code
this.anything//error
self.anything//solved
}
});
您只需更改所有&#39; 此&#39;进入&#39; 自我&#39;一旦你启动了如上图所示的ctor功能!
答案 1 :(得分:1)
这种情况正在发生,因为此 不引用地图功能中的组件。
要修复它,你必须将传递它的上下文作为第二个参数绑定到map函数。
var commentNodes = this.props.data.map(function(comment) {
return (
<Addcontenttotable onChange= {this.props.onChange} taskName={comment.taskName} standarDescription={comment.standarDescription} emplComment={comment.emp_comment} empRating={comment.empRating} key={comment.id} reviewComment={comment.review_comment} reviewRating={comment.review_rating} >
</Addcontenttotable>
);
},this);
如果您使用的是ES6,则可以使用胖箭头功能来保留上下文。
var commentNodes = this.props.data.map((comment) => {
return (
<Addcontenttotable onChange= {this.props.onChange} taskName={comment.taskName} standarDescription={comment.standarDescription} emplComment={comment.emp_comment} empRating={comment.empRating} key={comment.id} reviewComment={comment.review_comment} reviewRating={comment.review_rating} >
</Addcontenttotable>
);
});
答案 2 :(得分:1)
将this
传递到地图功能this.props.data.map(function(comment) { }, this);
或定义var self = this
并在地图功能中使用self.props
。
var TablefortaskList = React.createClass({
render: function() {
var commentNodes = this.props.data.map(function(comment) {
return (
<Addcontenttotable onChange= {this.props.onChange} taskName={comment.taskName} standarDescription={comment.standarDescription} emplComment={comment.emp_comment} empRating={comment.empRating} key={comment.id} reviewComment={comment.review_comment} reviewRating={comment.review_rating} >
</Addcontenttotable>
);
}, this);
return (
<tbody>{commentNodes}</tbody>
);
}
});