我在这些事件中包含事件和日志的JSON文件,示例如下所示:
{
"sessionEvents": [
{
"u": "BC0F6A3A2840B6F48386BABC5F34B480BA4F9929",
"v": "0.1.0",
"dv": "Unidentified",
"t": 1462924115818,
"uid": "",
"len": 148012,
"by": 0,
"g": "U",
"cy": "PH",
"cr": "Unknown",
"dm": "O+ Xfinit",
"lat": 0.0,
"lon": 0.0,
"l": [
{
"e": "100_SESSION_START",
"o": 24,
"d": 147988,
"p": {
"User_Timezone": "-08:00",
"Session_nb": "0",
"Energy_Balance": "89",
"Global_Playtime": "0",
"Device_id": "75e64b654c01949",
"Game_Language": "en",
"Connection_Type": "WIFI",
"User_Country": "US",
"Push_Impact": "None"
}
},
{
"e": "008_TUTORIAL_STEP_OTHER",
"o": 7561,
"d": 0,
"p": {
"Screen_id": "scene_screen",
"Misclicks": "0",
"Tutorial_Step": "19",
"Average_Time_Per_Frame": "0",
"Total_Time": "0"
}
}
]
},
{
"u": "C950FC733D883E11E36E15A705E05A3CC7748C3A",
"v": "0.1.0",
"dv": "OPPO Mirror 5",
"t": 1462908916463,
"uid": "",
"len": 5368,
"by": 0,
"g": "U",
"cy": "PH",
"cr": "Unknown",
"dm": "A51w",
"lat": 0.0,
"lon": 0.0,
"l": [
{
"e": "100_SESSION_START",
"o": 169,
"d": 5199,
"p": {
"User_Timezone": "-08:00",
"Session_nb": "0",
"Energy_Balance": "0",
"Global_Playtime": "0",
"Device_id": "d0de71513e48fba",
"Game_Language": "en",
"Connection_Type": "WIFI",
"User_Country": "US",
"Push_Impact": "None"
}
}
]
}
]
}
正如你所看到的,有一个第二级对象“l”包含事件的日志,第三级“p”包含参数,它给我带来了痛苦。我正在尝试将其转换为数据框,但我只需要表中的“100_SESSION_START”日志值(所有参数名称“l”和“p”名称都相同),另外,我需要添加所有来自更高级别对象的参数 - 事件('u','v','dv','t'......)。有没有人知道如何用户R?
upd:在结果中,拥有这样的表会很好 click
答案 0 :(得分:1)
假设您已将json
文件加载到data
变量
data <- fromJSON("/home/joel/tmp/input.json")
然后,您可以根据需要迭代每个事件和事件的每个日志:
n<-length(data$sessionEvents$u)
for (i in 1:n) { # Iterate over events
print(data$sessionEvents$u[i])
print(data$sessionEvents$v[i])
print(data$sessionEvents$dv[i])
print(data$sessionEvents$t[i])
m<-length(data$sessionEvents$l[i][[1]]$e)
for(j in 1:m){ # Iterate over logs
print(data$sessionEvents$l[i][[1]]$e[j])
}
}
希望它有所帮助。
答案 1 :(得分:0)
您可以使用name: (foo)
version: (1.0.0)
description:
entry point: (index.js)
test command:
git repository:
keywords:
author:
license: (ISC)
执行此类操作。
lapply