在我的django项目中,我正在使用遗留数据库,该数据库有一个包含多个主键的表。我面临的问题是,当我在某个模型实例上调用save()
方法时,Django ORM错误地构造了SQL查询。
例如,我有以下模型:
class MyTable(models.Model):
field_1 = models.IntegerField(primary_key=True)
field_2 = models.BooleanField(default=False, null=False)
field_3 = models.BooleanField(default=False, null=False)
user = models.ForeignKey(
CustomUser, models.DO_NOTHING, db_column='userid', primary_key=True)
class Meta:
managed = False
db_table = 'my_table'
unique_together = (('user', 'field_1'),)
我得到了这样的Model&#39实例:mytable_instance = MyTable.objects.all()[0]
。然后我想修改那个实例:
mytable_instance.field_2 = True
mytable_instance.field_2.save()
然而,Django ORM执行此查询:
{'sql': 'UPDATE `my_table` SET `field_2` = 1, `field_3` = 0 WHERE `my_table`.`field_1` = 123', 'time': '0.000'}
哪个不正确,因为它会为field_2
中field_3
的所有行设置my_table
和field_1 = 123
的新值
我该如何克服这个问题?我需要这样的SQL查询:
'UPDATE `my_table` SET `field_2` = 1, `field_3` = 0 WHERE `my_table`.`field_1` = 123 AND `my_table`.`user_id` = 1'
编辑:完整代码
旧数据库表的模型:
class MyTable(models.Model):
field1_id = models.IntegerField(db_column='field1id', primary_key=True)
is_favorite = models.BooleanField(db_column='isfavorite', default=False, null=False)
is_admin = models.BooleanField(db_column='isadmin', default=False, null=False)
role = models.IntegerField(default=USER_GUEST, null=False)
field2 = models.BooleanField(null=False, default=True)
field3 = models.BooleanField(null=False, default=True)
is_active = models.BooleanField(db_column='isactive', null=False, default=True)
user = models.ForeignKey(
CustomUser, models.DO_NOTHING, db_column='userid', primary_key=True)
DB_NAME = 'default'
class Meta:
managed = False
db_table = 'mytable'
unique_together = (('user', 'field1_id'),)
查询:
>>> from web_services.apps.my_app.models import MyTable
>>> g = MyTable.objects.get(field1_id=12)
>>> g.is_active = True
>>> g.save()
>>> connection.queries[-1]
{'time': '0.000', 'sql': 'UPDATE `mytable` SET `isfavorite` = 0, `isadmin` = 1, `role` = 3, `field2` = 1, `field3` = 1, `isactive` = 1 WHERE `mytable`.`field1id` = 12'}
但我需要:
{'time': '0.000', 'sql': 'UPDATE `mytable` SET `isfavorite` = 0, `isadmin` = 1, `role` = 3, `field2` = 1, `field3` = 1, `isactive` = 1 WHERE `mytable`.`field1id` = 12' AND `mytable`.`userid` = 1'}
答案 0 :(得分:1)
让我们看看这两个问题:
UPDATE `mytable`
SET `isfavorite` = 0, `isadmin` = 1, `role` = 3, `field2` = 1, `field3` = 1, `isactive` = 1
WHERE `mytable`.`field1id` = 12
和
UPDATE `mytable`
SET `isfavorite` = 0,`isadmin` = 1, `role` = 3, `field2` = 1, `field3` = 1, `isactive` = 1
WHERE `mytable`.`field1id` = 12' AND `mytable`.`userid` = 1
两者之间的唯一区别是AND userid=1
位。
当你说
时确实是对的它将为field_2和field_3设置所有行的新值 my_table with field1_id = 12
只有一行这样。为什么?因为您已将field_id定义为主键。这保证了只有一行,其中field1_id = N,其中N是任意整数。
所以django查询表现得很完美。