Question

我正在编写一个将数据存储到XML的程序。我不得不将数据从XML提取到DataGridView并编辑XML元素值。我尝试了很多代码，但它没有用。我究竟做错了什么？哪一个更容易。 Linq命令或XMLWriter，XMLReader方式???? 下面是代码：

private void button2_Click(object sender, EventArgs e)
        {
            string sid = textBox1.Text;
            string fname = textBox3.Text;
            string lname = textBox2.Text;
            string address = textBox4.Text;
            string gender = radioButton1.Checked ? "эр" : "эм";

            XmlDocument doc = new XmlDocument();
            doc.Load("student.xml");
            string tempid = doc.SelectSingleNode("root/Student/ID").InnerText;
            if(tempid == sid)
            {
                doc.SelectSingleNode("root/Student/Fname").InnerText = fname;
                doc.SelectSingleNode("root/Student/Lname").InnerText = lname;
                doc.SelectSingleNode("root/Student/Address").InnerText = address;
                doc.SelectSingleNode("root/Student/Gender").InnerText = gender;
            }

和XML：

<?xml version="1.0" encoding="UTF-8"?>

-<root>


-<Student>

<ID>B140030123</ID>

<FName>Kent</FName>

<LName>Wayne</LName>

<Address>Gotham</Address>

<Gender>эр</Gender>

</Student>

</root>

如何循环请帮助:(

private void button2_Click(object sender, EventArgs e)
        {
            string sid = textBox1.Text;
            string fname = textBox3.Text;
            string lname = textBox2.Text;
            string address = textBox4.Text;
            string gender = radioButton1.Checked ? "эр" : "эм";

            XmlDocument doc = new XmlDocument();
            doc.Load("student.xml");
            XmlNode node = doc.DocumentElement;
            string tempid = doc.SelectSingleNode("root/Student/ID").InnerText;
            foreach (var temp in doc.SelectSingleNode("root/Student/ID"))
            {


                if (tempid == sid)
                {
                    doc.SelectSingleNode("root/Student/FName").InnerText = fname;
                    doc.SelectSingleNode("root/Student/LName").InnerText = lname;
                    doc.SelectSingleNode("root/Student/Address").InnerText = address;
                    doc.SelectSingleNode("root/Student/Gender").InnerText = gender;
                }
            }

            doc.Save("student.xml");         



        }

Answer 1

修改XmlDocument对象不会更改xml文件。完成编辑后，您必须覆盖该文件。

XmlDocument doc = new XmlDocument();
doc.Load("student.xml");
string tempid = doc.SelectSingleNode("root/Student/ID").InnerText;
if(tempid == sid)
{
   doc.SelectSingleNode("root/Student/Fname").InnerText = fname;
   ...etc
}  

doc.Save("student.xml");

Answer 2

拥有XML结构，您可以使用一种简单的方法：

var dataSet = new DataSet();
dataSet.ReadXml("student.xml");

dataGridView.DataSource = dataSet.Tables["Student"];

这就是全部！

您可以在DataGridView中修改数据。您可以添加和删除行。

最后，将DataSet保存到文件中：

dataSet.WriteXml("student.xml");

在C＃中编辑XML值

2 个答案: