没有Pojo编辑：

Question

我有以下JSON结构，我想解析成Java对象。是否有我可以使用的现有库，或者我应该编写自定义代码来解析。示例json结构和java类如下所示。

JSON：

"name": "hierarchy",
"value": "[
  {
    "name": "solutionid",
    "value": "String"
  },
  {
    "name": "groupcode",
    "value": "String"
  },
  {
    "name": "dealhashid",
    "value": "String"
  },
  {
    "name": "keyinfo_customername",
    "value": "String"
  },
  {
    "name": "keyinfo_prequalificationnumber",
    "value": "String"
  },
  {
    "name": "keyinfo_orderactiontype",
    "value": "String"
  }
]"

Java对象：

class Hierarchy {
    String solutionId;
    String groupCode;
    KeyInfo keyInfo;

    public String getSolutionId() {
        return solutionId;
    }

    public void setSolutionId(String solutionId) {
        this.solutionId = solutionId;
    }

    public String getGroupCode() {
        return groupCode;
    }

    public void setGroupCode(String groupCode) {
        this.groupCode = groupCode;
    }

    public KeyInfo getKeyInfo() {
        return keyInfo;
    }

    public void setKeyInfo(KeyInfo keyInfo) {
        this.keyInfo = keyInfo;
    }
}

class KeyInfo {
    String customerName;
    String orderActionType;

    public String getCustomerName() {
        return customerName;
    }

    public void setCustomerName(String customerName) {
        this.customerName = customerName;
    }

    public String getOrderActionType() {
        return orderActionType;
    }

    public void setOrderActionType(String orderActionType) {
        this.orderActionType = orderActionType;
    }
}

Answer 1

使用Gson lib

定义Pojo

class Pojo {

    @Override
    public String toString() {
        return "Pojo [name=" + name + ", value=" + value + "]";
    }

    private String name;
    private List<Value> value;
}

class Value {

    private String name;
    private String value;

    @Override
    public String toString() {
        return "Value [name=" + name + ", value=" + value + "]";
    }

}

将字符串解析为pojo对象：

String json = "{\"name\": \"hierarchy\",\"value\": [  {    \"name\": \"solutionid\",    \"value\": \"String\"  },"
                + "           {    \"name\": \"groupcode\",    \"value\": \"String\"  },  {    \"name\": \"dealhashid\",    \"value\": \"String\""
                + "           },  {    \"name\": \"keyinfo_customername\",    \"value\": \"String\"  },  {    \"name\": \"keyinfo_prequalificationnumber\","
                + "         \"value\": \"String\"  },  {    \"name\": \"keyinfo_orderactiontype\",    \"value\": \"String\"  }]}";

Gson g = new Gson();
Pojo p = g.fromJson(json, Pojo.class);
System.out.println(p);

没有Pojo编辑：

String json = "{\"name\": \"hierarchy\",\"value\": [  {    \"name\": \"solutionid\",    \"value\": \"String\"  },"
                + "           {    \"name\": \"groupcode\",    \"value\": \"String\"  },  {    \"name\": \"dealhashid\",    \"value\": \"String\""
                + "           },  {    \"name\": \"keyinfo_customername\",    \"value\": \"String\"  },  {    \"name\": \"keyinfo_prequalificationnumber\","
                + "         \"value\": \"String\"  },  {    \"name\": \"keyinfo_orderactiontype\",    \"value\": \"String\"  }]}";

Gson g = new Gson();
JsonObject p = g.fromJson(json, JsonObject.class);
System.out.println(p.get("name"));
System.out.println(p.get("value"));

现在您可以使用名称和值...

JSON名称值对在Java中解析

1 个答案:

没有Pojo编辑：