Question

我收到错误从对象类型System.Web.UI.WebControls.TextBox到已知的托管提供程序本机类型不存在映射。

尝试将数据从输入表单上传到我的数据库时。如果有人认为他们可以提供帮助，那就是我的代码。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.Configuration;
using System.Data.SqlClient;
using System.IO;

public partial class register : System.Web.UI.Page

{
    protected void Page_Load(object sender, EventArgs e)
    {
        string elmtreeconnect = WebConfigurationManager.ConnectionStrings["elmtreeconnect"].ConnectionString;
        SqlConnection myConnection = new SqlConnection(elmtreeconnect);
    }
    protected void uploadbutton_Click(object sender, EventArgs e)
    {

        string UpPath = Server.MapPath("~/files/");

        Random r = new Random();
        int rInt = r.Next(0, 10000);

        if (!Directory.Exists(UpPath))
        {
            Directory.CreateDirectory(UpPath);

        }
        else
        {
            int imgSize = myimage.PostedFile.ContentLength;
            string imgName = myimage.FileName;
            string imgPath = "~/files/" + rInt + imgName;

            if (myimage.PostedFile.ContentLength > 1500000)
            {
                Page.ClientScript.RegisterClientScriptBlock(typeof(Page), "Alert", "alert('File is too big.')", true);
            }
            else
            {
                //then save it to the Folder
                myimage.SaveAs(Server.MapPath(imgPath));
                // myinfo.Text = "file " + imgPath + " uploaded";
            }


        }
        string connectionString = WebConfigurationManager.ConnectionStrings["elmtreeconnect"].ConnectionString;
        SqlConnection myConnection = new SqlConnection(connectionString);

        // myConnection.ConnectionString is now set to connectionString.
        myConnection.Open();

        string img = rInt + myimage.FileName;
        string passworddata = upassword.Text;
        string usernamedata = uname.Text;
        string addressdata = uadd.Text;
        string emaildata = ueadd.Text;
        string instdata = ulearning.Text;
        int userleveldata = Convert.ToInt16(typeID.SelectedValue);
        int number = Convert.ToInt32(unumber.Text);

        string query = "INSERT INTO user(uname, pword, address, email, phone, image, learning, typeID) VALUES(@name, @pass, @add, @email, @number, @image, @inst, @type)";

        SqlCommand myCommand = new SqlCommand(query, myConnection);

        //create a parameterised object
        myCommand.Parameters.AddWithValue("@name", usernamedata);
        myCommand.Parameters.AddWithValue("@pass", passworddata);
        myCommand.Parameters.AddWithValue("@add", addressdata);
        myCommand.Parameters.AddWithValue("@email", emaildata);
        myCommand.Parameters.AddWithValue("@number", unumber);
        myCommand.Parameters.AddWithValue("@img", myimage);
        myCommand.Parameters.AddWithValue("@inst", ulearning);
        myCommand.Parameters.AddWithValue("@type", userleveldata);


        myCommand.ExecuteNonQuery();




        myConnection.Close();



    }
}

Answer 1

错误来自此行myCommand.Parameters.AddWithValue("@number", unumber);。 unumber是一个文本框，您将从文本框中提取值到int变量号。所以你应该使用那个数字变量作为参数值。

应纠正以下几行

myCommand.Parameters.AddWithValue("@number", unumber);
myCommand.Parameters.AddWithValue("@img", myimage);
myCommand.Parameters.AddWithValue("@inst", ulearning);

要

myCommand.Parameters.AddWithValue("@number", number);
myCommand.Parameters.AddWithValue("@img", img);
myCommand.Parameters.AddWithValue("@inst", instdata);

尝试将数据上传到我的数据库时出错

1 个答案: