Question

我正在尝试创建一个加密ATOM-128中任何给定字符串的Android应用程序例如：输入＆＃34;你好＆＃34; /输出＆＃34; MIH3 + / CC + qCC＆＃34; 我已经用c＃（windows桌面应用程序）尝试了它并且当我在android studio中尝试用java做同样的事情时它运行良好我有这样的结果：输入＆＃34;你好＆＃34; outut＆＃34; 2662144270646427486464＆＃34;

这是代码

public class ATOM {
public static String Encrypt(String clearText)
{
    String key = "/128GhIoPQROSTeUbADfgHijKLM+n0pFWXY456xyzB7=39VaqrstJklmNuZvwcdEC";
    StringBuilder result = new StringBuilder();
    int i = 0;
    int[] indexes = new int[4];
    int[] chars = new int[3];
    do
    {
        chars[0] = i + 1 > clearText.length() ? 0 : (int)clearText.toCharArray()[i++];
        chars[1] = i + 2 > clearText.length() ? 0 : (int)clearText.toCharArray()[i++];
        chars[2] = i + 3 > clearText.length() ? 0 : (int)clearText.toCharArray()[i++];
        indexes[0] = chars[0] >> 2;
        indexes[1] = ((chars[0] & 3) << 4) | (chars[1] >> 4);
        indexes[2] = ((chars[1] & 15) << 2) | (chars[2] >> 6);
        indexes[3] = chars[2] & 63;
        if ((char)chars[1] == 0)
        {
            indexes[2] = 64;
            indexes[3] = 64;
        }
        else if ((char)chars[2] == 0)
        {
            indexes[3] = 64;
        }

        for (int index : indexes)
        {
            result.append(index);
        }
    }
    while (i < clearText.length());
    return result.toString();
}
public static String Decrypt(String clearText)
{
    String key = "/128GhIoPQROSTeUbADfgHijKLM+n0pFWXY456xyzB7=39VaqrstJklmNuZvwcdEC";
    StringBuilder result = new StringBuilder();
    int[] indexes = new int[4];
    int[] chars = new int[3];
    int i = 0;
    do
    {
        indexes[0] = key.indexOf(i++);
        indexes[1] = key.indexOf(i++);
        indexes[2] = key.indexOf(i++);
        indexes[3] = key.indexOf(i++);
        chars[0] = (indexes[0] << 2) | (indexes[1] >> 4);
        chars[1] = (indexes[1] & 15) << 4 | (indexes[2] >> 2);
        chars[2] = (indexes[2] & 3) << 6 | indexes[3];
        result.append((char)chars[0]);
        if (indexes[2] != 64)
            result.append((char)chars[1]);
        if (indexes[3] != 64)
            result.append((char)chars[2]);
    }
    while (i < clearText.length());
    return result.toString();
}

}

Answer 1

查看StringBuilder doc：

public StringBuilder append (int i)

Appends the string representation of the specified int value. 
The int value is converted to a string according to the rule defined by valueOf(int).

所以每次打电话

result.append(index);

您附加实际数字的字符串表示形式。你需要做的首先是将你的int解析成char ASCII表示。

result.append(((char)index));

应该这样做。

链接到doc： http://developer.android.com/reference/java/lang/StringBuilder.html#append(int)

ATOM-128字符串加密/解密（Android Studio）

1 个答案: