Question

我有一个简单的工作NodeJS测试应用程序，包括express，mongodb和mongoose。至于现在，我试图清理我的代码并找到最佳实践。我的一个步骤是提取REST路线，但我在这方面遇到了问题，我也很困惑，可以做到这一点的方式，2016年最好的方法是什么？

我的代码（app.js）：

"use strict"
const express    = require('express');
const bodyParser = require('body-parser');
const mongoose   = require('mongoose');

const Subjects = require('./models/Subjects').model('Subjects');
const Students = require('./models/Students').model('Students');

const app = express();

app.use(express.static(__dirname + '/public'));
app.use(bodyParser.json());
app.use(bodyParser.urlencoded({
    extended: true
}));
mongoose.connect('mongodb://localhost/schoolapp');

app.get('/subjects', function(req, res) {
    Subjects.find({})
        .exec(function(err, subjects) {
            if(err) {
                res.send('error msg has occured');
            } else {
                res.json(subjects);
            }
        })
});

app.put('/subjects', function(req, res) {
    const query = {name: req.body.name};
    const update = {$inc: {votes: 1}};

    Subjects.findOneAndUpdate(query, update,
        function(err, newSubject) {
            if(err) {
                console.log('An error occured');
            } else {
                res.send(newSubject);
            }
        })
})

app.post('/subjects', function(req, res) {
    let newSubject = new Subjects();

    newSubject.name = req.body.name;
    newSubject.level = req.body.level;
    newSubject.votes = 0;

    newSubject.save(function(err, subject) {
        if(err) {
            res.send('error saving subject');
        } else {
            res.send(subject);
        }
    })
});

app.get('/students', function(req, res) {
    Students.find({})
        .exec(function(err, students) {
            if(err) {
                res.send('error saving students');
            } else {
                res.send(students);
            }
        })
})

app.post('/students', function(req, res) {
    let newStudent = new Students();

    newStudent.name = req.body.name;

    newStudent.save(function(err, student) {
        if(err) {
            res.send('error saving student');
        } else {
            res.send(student);
        }
    })
})

app.put('/students', function(req, res) {
    const query = {"_id": req.body.id};
    const update = {$push: {subjects: req.body.name}};

    Students.findOneAndUpdate(query, update,
        function(err, newSubject) {
            if(err) {
                res.send('something went wrong');
            } else {
                res.send(newSubject);
            }
        });
})

app.listen(3000, function() {
    console.log('app listening on port 3000');
});

我想将/students和/subjects解压缩为单独的文件，并在我的app.js中要求它们。

我尝试过3种不同结果的方法，包括：

module.exports = function(app) {
    app.get('/students', ...)
}

并在app.js中：

var students = require(./rest/students)(app);

非常感谢：）

Answer 1

由于mh-cbon，我已将其整理出来了。我只是想在这里发布我的解决方案，以防其他人在寻找问题。

app.js

'use strict';
const express    = require('express');
const bodyParser = require('body-parser');
const mongoose   = require('mongoose');

const app = express();

app.use(express.static(__dirname + '/public'));
app.use(bodyParser.json());
app.use(bodyParser.urlencoded({
    extended: true
}));

app.use('/subjects', require('./rest/subjects'));
app.use('/students', require('./rest/students'));

mongoose.connect('mongodb://localhost/schoolapp');

app.listen(3000, function() {
    console.log('app listening on port 3000');
});

students.js

'use strict';
const Students = require('../models/Students').model('Students');
const express  = require('express');
let router     = express.Router();

router.get('/', function(req, res) {
    Students.find({})
        .exec(function(err, students) {
            if(err) {
                res.send('error saving students');
            } else {
                res.send(students);
            }
        })
})

router.post('/', function(req, res) {
    let newStudent = new Students();

    newStudent.name = req.body.name;

    newStudent.save(function(err, student) {
        if(err) {
            res.send('error saving student');
        } else {
            res.send(student);
        }
    })
})

router.put('/', function(req, res) {
    const query = {"_id": req.body.id};
    const update = {$push: {subjects: req.body.name}};

    Students.findOneAndUpdate(query, update,
        function(err, newSubject) {
            if(err) {
                res.send('something went wrong');
            } else {
                res.send(newSubject);
            }
        });
})

module.exports = router;

注意：通过./rest/subjects指定app.js中的路径将使模块根目录'/'中的路径（请参阅students.js），与某些教程不同。

我也发现这篇文章很有用（因为它显示了一个简单的例子）： https://www.terlici.com/2014/09/29/express-router.html

导出nodejs REST路径（带快速）

1 个答案: