<?php
$sql ="SELECT id FROM yoring ORDER BY id ASC";
$name = $_POST["name"];
$designation=$_POST['designation'];
$company=$_POST['company'];
$email = $_POST["email"];
$mobile=$_POST['mobile'];
$workno=$_POST['workno'];
$address=$_POST['address'];
$association=$_POST['association'];
$password = $_POST["password"];
$username = $_POST["username"];
$code=$_POST['code'];
$id = 0;
$res = mysqli_query($con,$sql);
while($row = mysqli_fetch_array($res)){
$id = $row['id'];
}
$image = $_POST['image'];
$path = "uploads/$id.png";
$actualpath = "http://sumitmehra.esy.es/$path";
$insertquery = mysqli_prepare($con , "INSERT INTO yoring ( name ,designation , company, email, mobile, workno, address, association, password,username,code,pic) VALUES (?,?,?,?,?,?,?,?,?,?,?,?)");
mysqli_stmt_bind_param($insertquery , "ssssiissssis", $name, $designation , $company, $email ,$mobile, $workno, $address, $association, $password,$username,$code,$actualpath);
mysqli_stmt_execute($insertquery);
file_put_contents($path,base64_decode($image));
mysqli_stmt_close($insertquery);
mysqli_close($con);
?>
创建文件的服务器上文件目录的屏幕截图:
使用此代码创建的两个图像文件,其中一个是包含实际文件的.png,另一个实际名称为0kb的文件帮助我
答案 0 :(得分:0)
您已从数据库中覆盖了ID。在$ id = 0之后输入您的查询$ res。