Question

我有一个关于Javascript和PHP的奇怪问题。

这些是我的代码

<script>
<?php
        $servername = "localhost";
        $username = "root";
        $password = "rootroot";
        $dbname = "onlinerecruitment";

        // Create connection
        $conn = new mysqli($servername, $username, $password, $dbname);
        // Check connection
        if ($conn->connect_error) {
            die("Connection failed: " . $conn->connect_error);
        }

        $s_id = NULL;
        $pos_id = $_POST['position'];
        $s_name = $_POST['skill_name'];
        $s_wg = $_POST['skill_weight'];
        $click = $_POST['clicks'];

        $sum = array_sum($s_wg);

?>
var sum = '<?php array_sum($s_wg); ?>';

        if( sum != 10){
                    alert("Weight-score is over or lower than 10.");

        }else{

<?php
        for($i=0; $i <= $click; $i++){

                $sql = ("INSERT INTO required_skills VALUES ('".$s_id."' , '".$pos_id."' , '".$s_name[$i]."' ,'".$s_wg[$i]."')");

                $resultt = "";

                if ($conn->query($sql) == TRUE) {
                   $resultt = "FINISH";
                } else {
                   $resultt = "ERROR";
                }

        }

        $conn->close();
?>


        var Message = ' <?php  echo $resultt; ?>';
        if((Message + "") == "ERROR"){
        alert("Something wrong, please contract web admin.");
        }else{
        alert("Weight-score setup successful.");
        location.href = "Weight_Score_Setup.php"
        } 

    }

正如您所看到的那样，有If和Else条件，我测试此页面以获得“If”条件。结果变为“If”，但INSERT查询也工作，它不应该，因为它们都处于“Else”状态。我不知道如何解决这个问题。请帮忙。

Answer 1

如果ELSE转移到PHP逻辑

<script>
<?php
        $servername = "localhost";
        $username = "root";
        $password = "rootroot";
        $dbname = "onlinerecruitment";

        // Create connection
        $conn = new mysqli($servername, $username, $password, $dbname);
        // Check connection
        if ($conn->connect_error) {
            die("Connection failed: " . $conn->connect_error);
        }

        $s_id = NULL;
        $pos_id = $_POST['position'];
        $s_name = $_POST['skill_name'];
        $s_wg = $_POST['skill_weight'];
        $click = $_POST['clicks'];

        $sum = array_sum($s_wg);
        if( $sum != 10){
                    echo 'alert("Weight-score is over or lower than 10.");';

        }else{

        for($i=0; $i <= $click; $i++){

                $sql = ("INSERT INTO required_skills VALUES ('".$s_id."' , '".$pos_id."' , '".$s_name[$i]."' ,'".$s_wg[$i]."')");

                $resultt = "";

                if ($conn->query($sql) == TRUE) {
                   $resultt = "FINISH";
                } else {
                   $resultt = "ERROR";
                }

        }

        $conn->close(); 
?>

        var Message = ' <?php  echo $resultt; ?>';
        if((Message + "") == "ERROR"){
        alert("Something wrong, please contract web admin.");
        }else{
        alert("Weight-score setup successful.");
        location.href = "Weight_Score_Setup.php"
        } 

    }

Javascript同时执行If和Else条件（PHP）

1 个答案: