Question

基本上我正在尝试评估9种不同的语句并找到它们的最小绝对值。然后，我想将语句的NON绝对值返回到单元格中。这意味着要跨细胞扩展。所以我对此的输入是=getCorrectedRotation(E5:5,F5:5,F14:14)

我收到#REF错误。有什么想法吗？

function getCorrectedRotation(previous, current, step) {
  var r=0,s=0,t=0,u=0,v=0,w=0,x=0,y=0,z=0
  var points = step.length;
  var output = [];
  var i;
  for (i = 0; i < points; i++) {
   r = ((current[i]-previous[i])/step[i])
   s = (((current[i]+360)-previous[i])/step[i])
   t = (((current[i]-360)-previous[i])/step[i])
   u = (((current[i]+360)-(previous[i]+360))/step[i])
   v = (((current[i]+360)-(previous[i]-360))/step[i])
   w = (((current[i]-360)-(previous[i]+360))/step[i])
   x = (((current[i]-360)-(previous[i]-360))/step[i])
   y = ((current[i]-(previous[i]+360))/step[i])
   z = ((current[i]-(previous[i]-360))/step[i])
  switch (Math.min(Math.abs(r),Math.abs(s),Math.abs(t),Math.abs(u),Math.abs(v),Math.abs(w),Math.abs(x),Math.abs(y),Math.abs(z))) {
    case Math.abs(r):
      output.push(r);
      break;
    case Math.abs(s):
      output.push(s);
      break;
    case Math.abs(t):
      output.push(t);
      break;
    case Math.abs(u):
      output.push(u);
      break;
    case Math.abs(v):
      output.push(v);
      break;
    case Math.abs(w):
      output.push(w);
      break;
    case Math.abs(x):
      output.push(x);
      break;
    case Math.abs(y):
      output.push(y);
      break;
    case Math.abs(z):
      output.push(z);
      break;
  }
}
  return output;
}

Answer 1

在我看来，你的引用错误可能与Java的ArrayIndexOutOfBounds错误相当。我试着改变

var points = step.length;

到

var points = step.length-1;

并查看是否可以解决您的问题，因为大多数“长度”参数是元素的数量（即最大引用+1）。你可能只是引用了“最后一点”，它不存在，因为它在数组之外。

这个Google脚本有什么问题？

1 个答案: