Question

我是Play框架的新手并尝试制作一个项目。也许某些部分我会出错，如果有的话请纠正我。我有3个模型，分别是客户，身份和债务。客户有一个身份，有很多债务。虽然我试图只获得客户及其身份，但未来的结果包括其债务。我的错误在哪里？在我的模特中，我正在寻找错误的方式？

Customers.java

@Entity
@Table(name="customers")
public class Customers extends Model {

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
public int id;

public int identity_id;

@Formats.DateTime(pattern = "dd/MM/yy")
public Date register_date;

public boolean status;
public Date closing_date;

@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "dd-MM-yyyy HH:mm:ss")
public Date created_at;

@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "dd-MM-yyyy HH:mm:ss")
public Date updated_at;

@OneToOne
@JoinColumn(name="identity_id", referencedColumnName = "id", unique = true)
public Identities identity;

@OneToMany(mappedBy = "customer", cascade=CascadeType.ALL)
public List<Debts> debts;

public static final Finder<Long, Customers> find = new Finder<>(
        Long.class, Customers.class);

}

Identities.java

@Entity
@Table(name="identities")
public class Identities extends Model {

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
public int id;

@Constraints.Required
public int customer_id;

public Long citizen_no;
public String full_name;

@JsonSerialize(using = JsonDateSerializer.class)
public Date birthdate;

public Integer place_of_birth;
public String father_name;
public String mother_name;

@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "dd-MM-yyyy HH:mm:ss")
public Date created_at;

@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "dd-MM-yyyy HH:mm:ss")
public Date updated_at;

public static final Model.Finder<Long, Identities> find = new Model.Finder<>(
        Long.class, Identities.class);
}

Debts.java

@Entity
@Table(name="debts")
public class Debts extends Model {

@Id
public Long id;

public int customer_id;
public Integer payment_id;

@JsonSerialize(using = JsonDateSerializer.class)
public Date billed_date;

public Float cost;
public Float taxes;
public boolean status;

@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "dd-MM-yyyy HH:mm:ss")
public Date created_at;

@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "dd-MM-yyyy HH:mm:ss")
public Date updated_at;

@ManyToOne(cascade = CascadeType.ALL)
@JoinColumn(name = "customer_id", referencedColumnName = "id")
private Customers customer;


public static final Model.Finder<Long, Debts> find = new Model.Finder<>(
        Long.class, Debts.class);
}

CustomerController.java

public class CustomersController extends BaseController {

public Result show(long id) {

    Customers customer = Customers.find.select("*")
            .fetch("identity")
            .where()
            .eq("id", id)
            .findUnique();

    return ok(Json.toJson(customer));
  }
}

Ebean模型获取客户信息和身份，而不会通过@onetomany关系承担债务

0 个答案: