小巧玲珑的多重映射

时间:2016-05-03 14:38:42

标签: dapper

使用短小精悍。当我评价这个:

var trains =
                conn.Query<Train, TrainDriver, Train>(
                    "Select T.TrainId,T.OperatorId,T.TrainDescriptor,T.DriverId,TD.TrainDriverId,TD.Name,TD.Salary from trains as T" +
                    "Inner Join TrainDrivers as TD on (T.DriverId = TD.TrainDriverId)" +
                    "Where T.TrainId = @id", (t, td) =>
                    {
                        t.Driver = td;
                        return t;
                    }, new {id = id}, null, true, "TrainDriverId");

我似乎得到了一个SQLException:{“多部分标识符\”T.DriverId \“无法绑定。\ r \ n无法绑定多部分标识符\”T.TrainId \“。 \ r \ n无法绑定多部分标识符\“T.TrainId \”。\ r \ n无法绑定多部分标识符\“T.OperatorId \”。\ r \ n多部分标识符\“ T.TrainDescriptor \“无法绑定。\ r \ n多部分标识符\”T.DriverId \“无法绑定。”}

这些字段都存在,如果我删除SQL并在SQL Manager中单独运行查询,它就可以运行......

有什么想法吗?

1 个答案:

答案 0 :(得分:1)

您只是缺少SQL查询中的一些空格。尝试:

    var trains =
                    conn.Query<Train, Driver, Train>(
                        "Select T.TrainId,T.OperatorId,T.TrainDescriptor,T.DriverId,TD.TrainDriverId,TD.Name,TD.Salary from trains as T" +
                        " Inner Join TrainDrivers as TD on (T.DriverId = TD.TrainDriverId)" +
                        " Where T.TrainId = @id", (t, td) =>
                        {
                            t.Driver = td;
                            return t;
                        }, new { id = id }, null, true, "TrainDriverId");