构建此类时出现此错误:
Cannot convert value of type '(Response<InventoryCategory?, NSError>) -> ()' to expected argument type 'Response<_, NSError> -> Void'
import Foundation
import Alamofire
import ObjectMapper
import AlamofireObjectMapper
import RealmSwift
class ProductCategorySync {
static func get (){
Alamofire.request(ProductCategory.ReadAll())
.responseObject { (response: Response<InventoryCategory, NSError>) in
switch response.result {
case .Success:
let items = response.result.value
if let items = items?.result {
let realm = try! Realm()
try! realm.write {
for item in items {
realm.add(item, update: true)
}
}
}
case .Failure:
break
}
}
}
}
这里是Alamofire要求的课程:
import UIKit
import Alamofire
enum ProductCategory: URLRequestConvertible {
static let baseURLString = ApiConfig.baseURL
case ReadAll()
var method: Alamofire.Method {
switch self {
case .ReadAll:
return .POST
}
}
// MARK: URLRequestConvertible
var URLRequest: NSMutableURLRequest {
ApiConfig.model = ApiConfig.MODEL_PRODUCT_CATEGORY
let URL:NSURL! = NSURL(string: ProductCategory.baseURLString)
let mutableURLRequest = NSMutableURLRequest(URL: URL)
mutableURLRequest.HTTPMethod = method.rawValue
var param_detail : Array<Dictionary<String, AnyObject>> = Array()
switch self {
case .ReadAll():
ApiConfig.method = ApiConfig.METHOD_SEARCH_READ
param_detail.append(["opts" : ApiConfig.opts, "moduleDetail" : ApiConfig.moduleDetailArr])
let parameters = ["jsonrpc": "2.0", "method": "api", "params": param_detail, "id" : 1]
return Alamofire.ParameterEncoding.JSON.encode(mutableURLRequest, parameters: (parameters as! [String : AnyObject])).0
default:
return mutableURLRequest
}
}
}
代码在解析JSON数据时工作正常,但是当我添加用于将JSON映射到Realm的行时出错。
感谢您,感谢您的帮助。