Question

我有很多这种类型的文件.txt：

gulp.task('default', function () {
  gulp.src('css/*.css')
   .pipe(cssmin({ 
      showLog: true, 
      relativeTo: 'css/',
      target: 'css/min/', 
      keepBreaks: true
    }))
   .pipe(rename({ suffix: '.min' }))
   .pipe(gulp.dest('css/min'));
});

我想将其中一列的值除以另一个相同类型文件中的列值。以下是我到目前为止的情况：

name1.fits 0 0 4088.9 0. 1. 0. -0.909983 0.01386 0.91 0.01386 -0.286976 0.00379 2.979 0.03971 0. 0.
name2.fits 0 0 4088.9 0. 1. 0. -0.84702 0.01239 0.847 0.01239 -0.250671 0.00261 3.174 0.04749 0. 0.
#name3.fits 0 0 4088.9 0. 1. 0. -0.494718 0.01168 0.4947 0.01168 -0.185677 0.0042 2.503 0.04365 0. 0.
#name4.fits 0 1 4088.9 0. 1. 0. -0.751382 0.01342 0.7514 0.01342 -0.202141 0.00267 3.492 0.07224 0. 0.
name4.fits 0 1 4088.961 0.01147 1.000169 0. -0.813628 0.01035 0.8135 0.01035 -0.217434 0.00196 3.515 0.04045 0. 0.

但是我得到x的相同值。例如，如果第一组数据是4089.txt，第二组（4026.txt）是：

with open('4026.txt','r') as out1, open('4089.txt', 'r') as out2, \
     open('4116.txt', 'r') as out3, open('4121.txt', 'r') as out4, \
     open('4542.txt', 'r') as out5, open('4553.txt', 'r') as out6:

    for data1 in out1.readlines():
        col1 = data1.strip().split()
        x = col1[9]

    for data2 in out2.readlines():
        col2 = data2.strip().split()
        y = col2[9]

    f = float(y) / float(x)
    print f

我希望将每个文件的第9列分开，只取每列的第一个元素name1.fits 0 0 4026.2 0. 1. 0. -0.617924 0.01749 0.6179 0.01749 -0.19384 0.00383 2.995 0.09205 0. 0. name2.fits 0 0 4026.2 0. 1. 0. -0.644496 0.01218 0.6445 0.01218 -0.183373 0.00291 3.302 0.05261 0. 0. #name3.fits 0 0 4026.2 0. 1. 0. -0.507311 0.01557 0.5073 0.01557 -0.176148 0.00472 2.706 0.07341 0. 0. #name4.fits 0 1 4026.2 0. 1. 0. -0.523856 0.01086 0.5239 0.01086 -0.173477 0.00279 2.837 0.05016 0. 0. name4.fits 0 1 4026.229 0.0144 1.014936 0. -0.619708 0.00868 0.6106 0.00855 -0.185527 0.00189 3.138 0.04441 0. 0.，但我得到0.91/0.6179 = 1.47。

Answer 1

发生的事情是你拥有的代码是捕获for循环中的最后一个值并将其除以。您应该在for循环的每个阶段进行除法以获得正确的除法。

更简单的方法是将所有值放在列表中例如 x = [0.0149,0.01218,..etc]和y = [...]

然后使用numpy（或针对列表的for循环）划分两个列表。 请记住，它们都需要具有相同的尺寸才能正常工作。

示例代码：

with open('4026.txt','r') as out1, open('4089.txt', 'r') as out2,  open('4116.txt', 'r') as out3, open('4121.txt', 'r') as out4, open('4542.txt', 'r') as out5, open('4553.txt', 'r') as out6:

    # Build two lists
    x = []
    y = []

    for data1 in out1.readlines():                
        col1 = data1.strip().split()
        x.append(col1[9])

    for data2 in out2.readlines():    
        col2 = data2.strip().split()    
        y.append(col2[9])

    for i in range(0,len(x)):

        # Make sure the denominator is not zero
        if y[i] != 0:
           print (1.0 * x[i])/y[i]
        else:
           print "Not possible"

Answer 2

你可以这样做：

select * from INFORMATION_SCHEMA.COLUMNS
where column_name like '%someColumn%'

如下所示处理文件可能更好，因为它不需要首先将所有文件的全部内容读入内存，而是一次处理每一行：

TABLE_CATALOG

使用不同文件的列进行操作

2 个答案: