所以我必须让用户输入一个文本文件,我的程序应该搜索这个文本文件,一旦找到它,它就会在该文本文件中搜索一个单词,并计算一个单词的次数。数字出现在这个文件中。我在编写代码时遇到了问题,只是在文本文件中搜索单词。请帮忙。这就是我到目前为止所做的:
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main()
{
string dog;
int word;
int TheFile;
cout << "enter the name of file and I'll search for it: " << endl;
cin >> name;
//opening the file
TheFile.open(name, ios::out);
if (file)
{
cout << "enter the word you want to search for: " << endl;
cin >> word;
getline(file, word);
//stuck here
for (unsigned int Numline = 0; getline(TheFile, SearchWord);NumLine++)
if (SearchWord.find)
}
else
{
cout << "the file " << NameofFile << " does not exist!" << endl;
return 0;
}
}
答案 0 :(得分:0)
一旦你阅读了搜索词,你就想不管它。
之后,您希望将文件中的行读入其他(字符串)变量。然后,您要在该字符串中搜索搜索词(例如,使用input_line.find(search_word)
。
答案 1 :(得分:0)
这应该可以解决问题。使用while(getline(TheFile,Line))进行循环,然后使用string :: find在Line中搜索SearchWord。
#include <iostream>
#include <fstream>
#include <string>
#include <conio.h>
using namespace std;
int main()
{
string name;
cout << "enter the name of file : " << endl;
cin >> name;
// opening the file
fstream TheFile;
TheFile.open(name, ios::in);
if (TheFile.is_open())
{
string word; // hold the word user inputs to be searched for
cout << "enter the word: " << endl;
string Line;
unsigned int found = 0;
while (getline(TheFile, Line)) {
if (Line.find(word) != string::npos)
++found;
}
cout << "the word " << word << " was found " << found << " times" << endl;
}
else
{
cout << "the file " << name << " does not exist!" << endl;
}
cout << "press enter to exit " << endl;
int c = getch();
return 0;
}