我定义了两个POJO:
Class1 -
public class Class1 {
Map<String, Object> param1 = new HashMap<String, Object>();
Map<String, Object> param2 = new HashMap<String, Object>();
Object body;
// getters-setters...
}
Class2 -
public class Class2 {
private String name = null;
private String description = null;
private List<Integer> data = new ArrayList<Integer>();
// getters-setters...
}
body字段是动态的,所以我把它变成了Object类型。我使用swagger codegen
在运行时生成Class2 Pojo。所以基本上body
对象代表Class2。 Class1是固定类,字段是已知的。
json -
{
"param1" : {
"id" : 132
},
"param2" : {
"address" : "String"
},
"body" : {
"name" : "value",
"description" : "value",
"data" : [ ]
}
}
我可以在Json上面反序列化Class1:
ObjectMapper mapper = new ObjectMapper();
Class1 ij = mapper.readValue(new File(path_of_above_json), Class1.class);
param1 = ij.getParam1();
param2 = ij.getParam2();
Object body = ij.getBody();
我想将body字段映射到Class2。我可以用gson做同样的事情:
Class2 body1 = new Class2();
Gson gson = new GsonBuilder().registerTypeAdapter(Class2.class, new ResponseBodyDeserializer<Class2>()).create();
ObjectMapper mapper = new ObjectMapper();
InputStream in = MainClass.class.getResourceAsStream(path_of_above_json);
BufferedReader r = new BufferedReader(new InputStreamReader(in));
body1 = gson.fromJson(r , Class2.class);
附加类ResponseBodyDeserializer -
class ResponseBodyDeserializer<T> implements JsonDeserializer<T>
{
@Override
public T deserialize(JsonElement je, Type type, JsonDeserializationContext jdc)
throws JsonParseException
{
// Get the element from the parsed JSON
JsonElement content = je.getAsJsonObject().get("body");
// Deserialize it
return new Gson().fromJson(content, type);
}
}
我们能否与杰克逊达成同样的目的,以避免这一额外的课程?
谢谢!
答案 0 :(得分:1)
以下是代码的修改版本
public class Class1<T> {
Map<String, Object> param1 = new HashMap<String, Object>();
Map<String, Object> param2 = new HashMap<String, Object>();
T body;
// getters-setters...
}
ObjectMapper mapper = new ObjectMapper();
Class1 ij = mapper.readValue(new File(path_of_above_json), Class1<Class2>.class);
param1 = ij.getParam1();
param2 = ij.getParam2();
Class2 body1 = ij.getBody();
答案 1 :(得分:1)
public static class Class1<T> {
private Map<String, Object> param1 = new HashMap<String, Object>();
private Map<String, Object> param2 = new HashMap<String, Object>();
private T body;
}
并像这样使用它:
ObjectMapper mapper = new ObjectMapper();
Class1<Class2> ij = mapper.readValue(json, new TypeReference<Class1<Class2>>() {});
Map<String, Object> param1 = ij.getParam1();
Map<String, Object> param2 = ij.getParam2();
Class2 body = ij.getBody();