Question

如何在Drupal 8中按程序为节点创建Field Collection项。我尝试使用下面的代码，但它不起作用。＆＃39; field_abc_inside＆＃39;是Field Collection＆field 39. field_abc＆＃39;。

的领域

$field_collection_item = entity_create('field_collection_item', array(
            'field_name' => 'field_abc',
            'field_abc_inside' => array('value'=> 'Test data'),
        )); 
$field_collection_item->setHostEntity($node);
$field_collection_item->save();

Answer 1

$user_id = \Drupal::currentUser()->getAccount()->id();
$user = User::load($user_id);

$fc = FieldCollectionItem::create(array(
     "field_name" => "field_hobbies",
));

$fc->set('field_hobby_name', 'Watch TV');
$fc->setHostEntity($user);

Answer 2

那个代码对我有帮助，但我有一个观察。

\Drupal::currentUser() 是用户对象，这很清楚，因为它使用它来检索 id()。因此不需要在第 2 行再次使用 User::load()，冗余处理会导致函数运行时间更长。

// Get the current user object
$user = \Drupal::currentUser();

// Prepare the new Field Collection Item object
$fc = FieldCollectionItem::create(array(
     "field_name" => "field_hobbies",
));

// Sets more field values
$fc->set('field_hobby_name', 'Watch TV');
// Sets the host record; where the field collection will be attached into
$fc->setHostEntity($user);
// Saves it into an actual field collection record
$fc->save();

如何在Drupal 8中按代码创建Field Collection Item

2 个答案: