Question

当我将ubuntu从15.10升级到16.04时，我的yii2项目中出现了这个错误

SQLSTATE[42000]: Syntax error or access violation: 1055 Expression #3
of SELECT list is not in GROUP BY clause and contains nonaggregated column 
'iicityYii.opportunity_conditions.money' which is not functionally dependent 
on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by

正在执行的SQL是：

SELECT SUM(oc.money),op.id,oc.money,
            op.mantaghe,
            op.`time`, op.`id`, `op`.`logo`,
           `pd`.`user_id`, `op`.`name`, 
           `pd`.`co_name`, `op`.`address`, 
           `op`.`project_type_id`, `op`.`state_id`
FROM `opportunity` op 
INNER JOIN `profile_details` pd  ON op.user_id=pd.user_id  
INNER JOIN `opportunity_conditions` oc ON   op.id=oc.opportunity_id
GROUP BY `op`.`id`
ORDER BY `op`.`id` DESC

如何解决我的问题？

Answer 1

运行：

sudo mysql -u root -p

并更改MySQL服务器实例的SQL模式：

mysql > SET GLOBAL sql_mode=(SELECT REPLACE(@@sql_mode,'ONLY_FULL_GROUP_BY',''));

另一种方法是使用MySQL配置。转到/etc/mysql/my.cnf：

添加一个部分 [mysqld]并在其下方添加声明 sql_mode = ""
重启mysql服务：
```
sudo systemctl restart mysql
```

Answer 2

在使用MySql的laravel中转到文件config / database.php，它将数组MySql mode strict更改为false。

'connections' => [
    'mysql' => [
        'driver' => 'mysql',
        'host' => env('DB_HOST', '127.0.0.1'),
        'port' => env('DB_PORT', '3306'),
        'database' => env('DB_DATABASE', 'forge'),
        'username' => env('DB_USERNAME', 'forge'),
        'password' => env('DB_PASSWORD', ''),
        'unix_socket' => env('DB_SOCKET', ''),
        'charset' => 'utf8mb4',
        'collation' => 'utf8mb4_unicode_ci',
        'prefix' => '',
        'strict' => false, //from true
        'engine' => null,
    ],
],

Answer 3

在您的选择中，您有一个聚合函数和一组列名称，该错误告诉您没有在group by子句中指定正确的列名列表。可能是你应该在组中添加更多的列名称，可能与profile_details, opportunity_conditions表

相关

您还有,(opportunity.id),(opportunity_conditions.money), (opportunity.mantaghe),为什么()如果您需要总和，则必须向所有列添加总和

sum(opportunity.id), sum(opportunity_conditions.money),

和（opportunity.mantaghe），

否则，如果这些是普通列，则应使用正常的sintax而不使用（）

opportunity.id, opportunity_conditions.money,opportunity.mantaghe,

我试图重写可能的查询

 SELECT SUM(opportunity_conditions.money),
        `opportunity`.`id`,
        `opportunity_conditions.money`,
        `opportunity.mantaghe`, 
        `opportunity`.`time`, 
        `opportunity`.`logo`, 
        `profile_details`.`user_id`,
        `opportunity`.`name`, 
        `profile_details`.`co_name`,
        `opportunity`.`address`, 
        `opportunity`.`project_type_id`,
        `opportunity`.`state_id` 
FROM `opportunity` 
INNER JOIN `profile_details` ON `opportunity`.`user_id`= `profile_details`.`user_id` 7
INNER JOIN `opportunity_conditions` ON `opportunity`.`id`=`opportunity_conditions`.`opportunity_id` 
GROUP BY`opportunity`.`id`,   `profile_details`.`user_id`,`opportunity_conditions.money`,  
ORDER BY `opportunity`.`id` DESC

with group by the essential column name（i hope）

GROUP BY`opportunity`.`id`,   `profile_details`.`user_id`,`opportunity_conditions.money`,

Answer 4

请复制此行并运行它。它对我有用。

SET GLOBAL sql_mode=(SELECT REPLACE(@@sql_mode,'ONLY_FULL_GROUP_BY',''));

Youtube video to fix this

Answer 5

解决方案是编辑MySQL配置文件，因为配置将在每次重新启动后恢复...

class Species(models.Model):
    name = models.CharField()

class SpeciesAttribute(models.Model):
    species = models.ForeignKey(Species)
    name = models.CharField()

class Animal(models.Model):
    name = models.CharField()
    species = models.ForeignKey(Species)

class AnimalAttributeValue(models.Model):
    animal = models.ForeignKey(Animal)
    attribute = models.ForeignKey(SpeciesAttribute)
    value = models.CharField()

并添加

sudo nano /etc/mysql/mysql.conf.d/mysqld.cnf

然后重新启动

[mysqld]
sql-mode=""

在ubuntu 18.04上工作。

Answer 6

对于CentOS8，我使用webmin配置文件/etc/my.cnf.d/mysql-server.cnf

[mysqld] sql-mode =“”

Answer 7

谢谢，这对我有帮助，但这不会将其设置为永久，并且每次重启后都会恢复。

所以你应该在配置文件中设置它（例如[mysqld]部分中的/etc/mysql/my.cnf），以便在MySQL重启后更改仍然有效：

配置文件：/etc/mysql/my.cnf

[mysqld]
sql-mode="STRICT_TRANS_TABLES,NO_ENGINE_SUBSTITUTION"

Answer 8

只需对以下内容严格设置为假

Config > database.php  set 'strict' => false,

Answer 9

您可以将select id, level_cd_1 as level_cd from Test_2020 where level_cd_1 is not null union all select id, level_cd_2 from Test_2020 where level_cd_2 is not null用于未聚合的列。因此，您可以使用：

 select id, coalesce(level_cd_1,level_cd_2)as leve_cd from Test_2020 where 
  (level_cd_1 is not null or level_cd_2 is not null)

更多详细信息here。

Answer 10

将查询更新为：

    SELECT SUM(any_value(oc.money)),op.id,any_value(oc.money) as money,
            op.mantaghe,
            op.`time`, op.`id`, `op`.`logo`,
           any_value(`pd`.`user_id`) as user_id, `op`.`name`, 
           any_value(`pd`.`co_name`) as co_name, `op`.`address`, 
           `op`.`project_type_id`, `op`.`state_id`
FROM `opportunity` op 
INNER JOIN `profile_details` pd  ON op.user_id=pd.user_id  
INNER JOIN `opportunity_conditions` oc ON   op.id=oc.opportunity_id
GROUP BY `op`.`id`
ORDER BY `op`.`id` DESC

了解
当查询包含group by时，您只应从要分组的表中选择列，否则，应使用any_value()函数从其他表中调用列。

我个人尝试不更新sql_mode全局变量。

您可以在https://dev.mysql.com/doc/refman/5.7/en/group-by-handling.html

上了解更多信息

SQLSTATE [42000]：语法错误或访问冲突：1055 SELECT列表的表达式＃3不在GROUP BY子句中并包含nonaggregated

10 个答案: