我有两次调用我的网络服务,他们将在同一页面中填充两个不同的网格部分。
我不希望在Web服务调用返回之前显示该页面。
这是它的样子:
在ABCCtrl.js ............
if (params) {
//I set the please wait dialog on
$scope.pleaseWait = { "display": "block" };
//I hit the first service call and it will populate myFirstUIGrid
TransactionApiServices.getApiUnmergeProcessDetails(params).then(function (results) {
$scope.gridOptions_PR.data = "";
$scope.gridOptions_PR.data.length = 0;
$scope.gridOptions_PR.data = results.data;
console.log(results);
});
//I hit the second service call and it will populate mySecondUIGrid
TransactionApiServices.getApiUnmergeRequestDetails(params).then(function (results) {
$scope.gridOptions_RQ.data = "";
$scope.gridOptions_RQ.data.length = 0;
$scope.gridOptions_RQ.data = results.data;
console.log(results);
});
在两个网格填充后,我只想set the please wait off
并显示网格。
$scope.toggleDetails = { "display": "block" };
$scope.toggleHeader = { "display": "block" };
$scope.pleaseWait = { "display": "none" };
这是包含两个ui网格的页面:
<div class="home-grid-content" ng-controller="TransactionDetailsUnmergeController">
<div ng-style="pleaseWait">
<div class="refresh" style="width:100%;height:100px;">
<h4>Please wait....</h4>
</div>
</div>
<div ng-style="toggleDetails">
<h3>Unmerge Request Log</h3>
<div ui-grid="gridOptions_RQ" ui-grid-selection class="" ui-grid-pagination ui-grid-auto-resize>
<div class="watermark" ng-show="!gridOptions.data.length">No data available</div>
</div>
<div class="grid-pager">
<uib-pagination boundary-links="true" total-items="totalItems" items-per-page="4" ng-change="pageChanged(currentPage)" ng-show="(totalItems>4) == true"
ng-model="currentPage" class="pagination" direction-links="false" id="HconstUnmerge_1"
first-text="«" last-text="»">
</uib-pagination>
</div>
<br/>
<h3>Unmerge Process Log</h3>
<div ui-grid="gridOptions_PR" ui-grid-selection class="" ui-grid-pagination ui-grid-auto-resize>
<div class="watermark" ng-show="!gridOptions.data.length">No data available</div>
</div>
<div class="grid-pager">
<uib-pagination boundary-links="true" total-items="totalItems" items-per-page="4" ng-change="pageChanged(currentPage)" ng-show="(totalItems>4) == true"
ng-model="currentPage" class="pagination" direction-links="false" id="HconstUnmerge_1"
first-text="«" last-text="»">
</uib-pagination>
</div>
<div style="margin-top:8px;">
<button type="button" class="btn btn-default pull-left" ng-click="backToDetailsPage()">Cancel</button>
</div>
</div>
</div>
答案 0 :(得分:1)
您可以使用$q.all([ array of promises ]).then(...)
。检查docs
所有(许诺);
将多个promises组合成一个promise,当所有输入promise都被解析时解析。
编辑:示例
var promises = [$timeout(angular.noop, 500), $timeout(angular.noop, 5000)];
$q.all(promises).then(function(results){
//This will be executed when both promises fulfill - after 5000ms
var promise1_result = results[0];
var promise2_result = results[1];
doStuff();
})
答案 1 :(得分:1)
你可以使用ng-hide和ng-show来实现这个
HTML:
<div ng-show='grid1 && grid2 '>grid1</div>
<div ng-show='grid1 && grid2 '>grid2</div>
<div ng-hide='grid1 && grid2 '>please wait</div>
JS
if (params) {
//I set the please wait dialog on
$scope.pleaseWait = { "display": "block" };
//I hit the first service call and it will populate myFirstUIGrid
TransactionApiServices.getApiUnmergeProcessDetails(params).then(function (results) {
$scope.grid1 = true
$scope.gridOptions_PR.data = "";
$scope.gridOptions_PR.data.length = 0;
$scope.gridOptions_PR.data = results.data;
console.log(results);
});
//I hit the second service call and it will populate mySecondUIGrid
TransactionApiServices.getApiUnmergeRequestDetails(params).then(function (results) {
$scope.grid2 = true
$scope.gridOptions_RQ.data = "";
$scope.gridOptions_RQ.data.length = 0;
$scope.gridOptions_RQ.data = results.data;
console.log(results);
});
答案 2 :(得分:1)
你没有提供与你的JS一起使用的HTML,所以我会为你做些什么。
我使用$timeout
代替TransactionApiServices.getApiUnmergeRequestDetails
但是如果你使用我在这个jsfiddle中所做的相同的想法,它应该可以工作。
HTML:
<body ng-app="MyApp" ng-controller="MyController">
<div id="loading-overlay" ng-class="{ 'display': loading }">
<div id="popup">
Please Wait... <!-- any other styling you want goes on this popup. -->
</div>
</div>
<div>
{{data}}
</div>
</body>
JS:
angular.module("MyApp", []);
angular.module("MyApp").controller("MyController", function ($scope, $timeout, $q) {
$scope.data = "";
var firstPromise = TransactionApiServices.getApiUnmergeProcessDetails(params).then(function() {
$scope.gridOptions_PR.data = "";
$scope.gridOptions_PR.data.length = 0;
$scope.gridOptions_PR.data = results.data;
console.log(results);
});
var secondPromise = TransactionApiServices.getApiUnmergeRequestDetails(params).then(function() {
$scope.gridOptions_RQ.data = "";
$scope.gridOptions_RQ.data.length = 0;
$scope.gridOptions_RQ.data = results.data;
console.log(results);
});
$scope.loading = true;
$q.all([firstPromise, secondPromise]).then(function () {
$scope.loading = false;
});
});
CSS:
#loading-overlay {
position: fixed;
display: none;
top: 0;
left: 0;
width: 100%;
height: 100%;
z-index: 100000;
background-color: #000000;
opacity: 0.5;
}
#loading-overlay.display {
display: block !important;
}
#popup {
margin: 0 auto;
width:75%;
margin-top: 100px;
color: rgba(255, 255, 255, 1);
}
https://jsfiddle.net/kszat61j/看到它的实际效果。
它没有那么多的造型,但我认为一般的想法是你想要的。
编辑:更改了代码以更清楚地与您的问题联系起来。希望这会有所帮助。
答案 3 :(得分:0)
甜美易懂您可以使用ng-hide或ng-show
myApp.controller('CheckServiceCtrl',function($scope){
$scope.service1=false;
$scope.service2=false;
//after returning data from service1 set
$scope.service1=true;
//after return data from service2 set
$scope.service2=true;
}
假设您正在以2个不同的div显示数据,并且根据您的要求,数据应仅在完成两个服务后显示 你应该声明div之类的。
<div ng-controller="CheckServiceCtrl" >
<div id="serivces" ng-show="service1 && service2">
<div id="service1" >
Display of service1
</div>
<div id="service2">
Display of service2
</div>
</div>
<div id=pleasewait" ng-hide="service1 && service2">
Please Wait....
</div>
</div>