Question

打印动物的最佳方式是什么，同时确保列出未来的动物而不更改代码？我的试训非常不成熟......

var animals = ["Cows", "Chickens", "Pigs", "Horses"];

var printFarm = function(a, b, c, d){

console.log("You have " + a + " " + animals[0]);
console.log("You have " + b + " " + animals[1]);
console.log("You have " + c + " " + animals[2]);
console.log("You have " + d + " " + animals[3]);

};

printFarm(3, 6, 17, 54);

Answer 1

以下两种方式......

var animals = ["Cows", "Chickens", "Pigs", "Horses"];

function printFarm(arrAnimals) {
    for (var i = 0; i < arrAnimals.length; i++) {
        var animalGroup = arrAnimals[i];
        var amount = printFarm.arguments[i + 1];
        if (amount) {
            console.log('You have ' + amount + ' ' + animalGroup + '.');
        } else {
            console.log('No amount was found for ' + animalGroup + '.');
        }
    }
}

printFarm(animals, 3, 6, 17, 54);

所以，你需要做的就是改变你的数组以包含一个新的动物，然后简单地将金额追加到printFarm函数调用的末尾，就像我上面所做的那样。或者，除了动物阵列之外，您还可以将一系列动物计数传递给该函数。

或者传递一组animalCount对象，这些对象具有动物的名称和计数作为对象的一部分。像这样......

var animals = [{ name:'cows', count:3 },
               { name:'chickens', count:6 },
               { name:'pigs', count:17 },
               { name:'horses', count:54 }];

function printFarm(arrAnimals) {
    for (var i = 0; i < arrAnimals.length; i++) {
        var animalGroup = arrAnimals[i];
        var name = animalGroup.name;
        var amount = animalGroup.count;
        console.log('You have ' + amount + ' ' + name + '.');
    }
}

printFarm(animals);

Answer 2

为什么不将整数数组传递给函数，然后使用animals数组或整数数组中的最小项数进行循环？

 var animals = ["Cows", "Chickens", "Pigs", "Horses"];

 var printFarm = function(animalCounts) {

      var index = Math.min(animals.length, animalCounts.length);

      for (var i = 0; i < index; i++) {
           console.log("You have " + animalCounts[i] + " " + animals[i];
      }
 }

 printFarm([1,2,3,4]);

Answer 3

更好的方法是创建一个Animal类并为每个所需的动物创建一个对象。这是一个粗略的例子，但显示了这个想法。

function Animal(type, count) {
  this.type = type;
  this.count = count;

  this.print = function() {
    console.log("You have " + this.count + " " + this.type);
  }
}

可能更好的方法是动物基类，每个新的动物类型都添加了子类化，但这样就可以了。

https://jsfiddle.net/f9n0en7e/

什么是农民“印刷动物”最有效的解决方案？

3 个答案: