Question

我有以下json结构

Appointment (Appointment name in model )
    |
    |___AppointmentList (appointmentLists name in model)
        |
        |__sync (sync name in model )
        |__subject
        |__time

现在我正在尝试获取sync = 1但它返回所有数据，无论sync是1还是0

 final Realm realm = getRealm();
        RealmResults<Appointment> appointment = 
            realm.where(Appointment.class).equalTo("appointmentLists.sync",NOT_SYNC).findAll();

realm.close();

它仅适用于以下情况

 RealmResults<AppointmentList> appointmentList = 
 realm.where(AppointmentList.class).equalTo("sync",RestApi.NOT_SYNC).findAll();


@JsonObject
public class Appointment extends RealmObject {

    @JsonField
    private String status;

    @JsonField
    private String errorMessage;

    @JsonField
    private String count;


    @PrimaryKey
    @JsonField
    private String userId;

    @JsonField
    private String organizationId;

    public String getUserId() {
        return userId;
    }

    public void setUserId(String userId) {
        this.userId = userId;
    }

    public String getOrganizationId() {
        return organizationId;
    }

    public void setOrganizationId(String organizationId) {
        this.organizationId = organizationId;
    }


    @JsonField(name ="appointments" , typeConverter = AppointmentListConverter.class)
    private RealmList<AppointmentList> appointmentLists;
   }

Answer 1

这是设计上的。您从您指定的类的角度进行查询，在本例中为Appointment。我们不会返回“部分”类，这听起来像是你正在寻找的。

如果您希望从Appointment引用您的父AppointmentList，那么它应该是AppointmentList的模型定义的一部分。现在它是您必须手动维护的参考，但我们有一个自动创建它的问题。该概念称为反向链接：https://github.com/realm/realm-java/issues/607

如果您想使用现有的转换器流程，我可能会使用realm.copyFromRealm并进行手动过滤：

Realm realm = getRealm();
RealmResults<Appointment> results = realm.where(Appointment.class).equalTo("appointmentLists.sync",NOT_SYNC).findAll();

List<Appointment> copiedResults = realm.copyFromRealm(results);
for (Appointment a : copiedResults ) {
  Iterator<AppointmentList> it = a.getAppointmentLists().iterator();
  while (it.hasNext()) {
    AppointmentList item = it.next();
    if (item.getSync() == RestApi.NOT_SYNC) {
      it.remove();
    }  
  }
}

sendNotSyncedAppointments(copiedList);

链接查询不在境界中工作

1 个答案: